JOptionDialog顯示堆棧如何？

Question

好的傢伙我需要這個實驗室是顯示堆棧，我在JOptionMessageDialog框中，我不知道如何顯示堆棧。我繼續顯示@ jkh24k54而不是整數集。

我的代碼：

import java.util.Random; 
import javax.swing.JOptionPane; 

public class Lab5 
{ 

    public static void main(String[] arg) 
    { 

Random rnd = new Random(); 

Stack<Integer> stack = new IStack<Integer>(); 
Stack<Integer> stack0= new IStack<Integer>(); 
Stack<Integer> stack1= new IStack<Integer>(); 
Stack<Integer> stack2= new IStack<Integer>(); 
int stream; 


for(int i=0;i<20;i++) 
{ 
    stream = rnd.nextInt(101); 
    stack.push(stream); 
    stack2.push(stream); 
} 
while(!stack2.isEmpty()) 
{ 
    int x = stack2.pop(); 
    stack.push(x); 
} 

    for(int i=0; i<20; i++) 
    { 
    int x= stack.pop(); 

    if(x%3==0) 
    stack0.push(x); 
    if(x%3==1) 
    stack1.push(x); 
    if(x%3==2) 
    stack2.push(x); 
} 

    while(!stack.isEmpty()) 
     System.out.print(stack.pop()+" "); 
    System.out.println(); 
    while(!stack0.isEmpty()) 
     System.out.print(stack0.pop()+" "); 
    System.out.println(); 
    while(!stack1.isEmpty()) 
     System.out.print(stack1.pop()+" "); 
    System.out.println(); 
    while(!stack2.isEmpty()) 
     System.out.print(stack2.pop()+" "); 
    System.out.println(); 

JOptionPane.showMessageDialog(null, "Original stack: "+ stack.toString()+ "\n"+ 
           " 0%3: "+stack0.toString()+"\n"+ "1%3: "+stack1.toString()+"\n"+ " 2%3: "+stack2.toString()); 

}}

Answer 1

您的通話在默認情況下，這就是爲什麼你得到@ jkh24k54打印其存儲位置的對象的默認toString（）方法。您需要重寫堆棧類的toString（）方法以返回數組中的元素的字符串。

一個例子：像這樣的東西添加到你的堆棧類。

@Override 
public String toString() 
{ 
    String returnString = ""; 
    for(int i = 0; i < yourarray.length; i++) 
    { 
     if(yourarray[i] != null) 
     { 
      returnString += yourarray[i]; 
     } 
     ////if you want to add spaces for null then add this 
     else 
     { 
      returnString += " "; 
     } 
     ////the else is probably not necessary for what you are doing 
    } 
    return returnString; 
}