PHP/MySQL的插入信息，如果標識的匹配否則插入不同的信息

Question

好了，這已經被修改還有3桌板，賬號，登錄

感謝布賴恩Moyles他那種給我一種頓悟

這裏是我的代碼

$query=$S->query(" 
    SELECT 
     `TBL`.`LAcc`, 
     `TBL`.`AId`, 
     `TBL`.`Add`, 
     `TBL`.`Lost`, 
     `TBL`.`LDate`, 
     `TBL`.`FDate` 

     FROM (
      SELECT 
       (SELECT SUM(`Add`) FROM `m_rules` GROUP BY `Group`) AS `Add`, 
       `S`.`Account` as `LAcc`, 
       `P`.`Id` as `AId`, 
       SUM(`S`.`Loss`*`S`.`Multiple`) AS `Lost`, 
       MAX(`S`.`Timestamp`) AS `LDate`, 
       MIN(`S`.`Timestamp`) AS `FDate` 
        FROM `log` AS S,`account` AS P 

      GROUP BY `P`.`Id` 
     ) as `TBL` 
     WHERE `TBL`.`FDate` <= NOW() 
     AND `TBL`.`LDate` >= DATE_SUB(NOW(), INTERVAL 1 DAY) 

") or die(mysql_error()); 

    while($Log=$S->fetch($query)) { 

     if($Log['AId']==$Log['LAcc']) { 
      $Score=$Log['Add']-$Log['Lost']; 
     } else { 
      $Score='Bonus'; 
     } 

     /* 
      echoing to see results 
     */ 
     echo $Log['AId'].' : '.$Score.'<br />'; 

     /* 
     This is what the query would look like Thanks to Bryan Moyles, 

     $S->query("INSERT INTO `board` (`Account`,`Score`, `Date`)VALUES('".$Log['Id']."', '".$Score."', 'NOW()') ON DUPLICATE KEY UPDATE Score = '".$Score."'"); 
     */ 
    } 

在這裏你去的所有結果：組按帳戶ID

Account Id:4, Log Account:5, Add: 97.64236, Lost:141.11371 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:05:48, Score:Bonus 
Account Id:5, Log Account:5, Add: 97.64236, Lost:141.11371 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:05:48, Score:-43.47135 
Account Id:6, Log Account:5, Add: 97.64236, Lost:141.11371 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:05:48, Score:Bonus 
Account Id:7, Log Account:5, Add: 97.64236, Lost:141.11371 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:05:48, Score:Bonus 
Account Id:8, Log Account:5, Add: 97.64236, Lost:141.11371 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:05:48, Score:Bonus 

GROUP BY登錄帳戶ID

Account Id:4, Log Account:4, Add: 97.64236, Lost:119.67095 LastDate:2012-05-04 22:07:46, FirstDate:2012-05-04 22:06:29, Score:-22.02859 
Account Id:4, Log Account:5, Add: 97.64236, Lost:542.30295 LastDate:2012-05-04 22:06:54, FirstDate:2012-05-04 22:05:48, Score:Bonus 
Account Id:4, Log Account:6, Add: 97.64236, Lost:43.59465 LastDate:2012-05-04 22:07:06, FirstDate:2012-05-04 22:07:06, Score:Bonus 

我看到的問題只是不知道該解決方案的..

解決了！

我在原來的查詢替換

FROM `log` AS S,`account` AS P 

隨着

FROM `account` AS `P` LEFT JOIN `log` AS `S` ON `P`.`Id`=`S`.`Account` 

（我修改，並改變了它在這之前），我有賬號並登錄反向與P一起。 Id = S。 Account哪些沒有工作，所以我只是交換日誌和帳戶，它的工作..不能相信這是問題，但謝謝你的幫助。

Answer 1

我不確定你會如何遇到日誌不存在的情況，因爲你正在從查詢結果中構建數據。但是，您要插入主鍵，並且可以捕獲重複的鍵錯誤，並相應地運行更新。

看看這篇文章 http://dev.mysql.com/doc/refman/5.0/en/insert-on-duplicate.html

$S->query("INSERT INTO `board` (`Account`,`Score`, `Date`)VALUES('".$Log['Id']."', '".$Score."', 'NOW()') ON DUPLICATE KEY UPDATE Score = '".$Score."'");