2014-01-10 107 views
0

這是我的插件工作的代碼需要插入2個數組到phpmyadmin,但錯誤的forach循環的PHP ...任何解決方案....任何替代解決方案如何插入?爲foreach()提供的無效參數任何解決方案

if (isset($_POST['addvenue'])) { 


<?php echo "<pre>".print_r($_POST['RoomTilte'],true)."</pre>"; 
echo "<pre>".print_r($_POST['Capacity'],true)."</pre>"; 

mysql_connect("localhost","root","");//database connection 
mysql_select_db("ossd"); 
$a=array($_POST['RoomTitle']); 
if (is_array($a)) 
{ 
    echo"yes it is array"; 
foreach ($_POST['RoomTitle'] as $row=>$name) 

{ 

    $Roomtitle = $name; 

    $Capacity = $_POST['Capacity'][$row]; 
    $RoomTitle= mysql_real_escape_string($name); 

    $Capacity = mysql_real_escape_string($_POST['Capacity'][$row]); 

    $order = "INSERT INTO wp_ossd_venue 
     (RoomTitle,Capacity) 
     VALUES 
     (".$RoomTitle.",".$Capacity.")"; 

    $result = mysql_query($order); 

} 
} 
if($result){ 
    echo("<br>Succesfully Added"); 
} else{ 
    echo("<br>Fail... Error"); 
} 

} 

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