Python正則表達式的問題

Question

我有這種類型的字符串：

s = "//name#1 un2 //name2#1 u13 //name3#3" 

我怎樣才能得到字符串這些陣列：

s1 [] = "//name, //name2, name3" 
s2 [] = "1, 2, 3" 

Answer 1

可能您正在尋找

>>> s1=", ".join(re.findall("(//.*?)#\d+",s)) 
>>> s2=", ".join(re.findall("#(\d+)",s)) 
>>> s1 
'//name, //name2, //name3' 
>>> s2 
'1, 1, 3' 
>>> 

Answer 2

這確實是只用一個正則表達式：

>>> s = "//name#1 un2 //name2#1 u13 //name3#3" 
>>> import re 
>>> x = re.findall(r"(\S+)#(\S+)", s) 
>>> [s1, s2] = [', '.join(y) for y in zip(*x)] 
>>> s1 
'//name, //name2, //name3' 
>>> s2 
'1, 1, 3'