8
我想創建一個簡單的登錄基於Zentask示例 - zentask - playframework,但是當我單擊登錄按鈕調用Application.authenticate操作時,它給運行時異常。我已經標有行 - 錯誤Playframework:[RuntimeException:java.lang.reflect.InvocationTargetException]
[RuntimeException: java.lang.reflect.InvocationTargetException]
Application.java
public class Application extends Controller {
.........
public static class Login
{
public String email;
public String password;
public String validate()
{
if (User.authenticate(email, password) == null) {
return "Invalid user or password";
}
return null;
}
}
public static Result authenticate()
{
Form<Login> loginForm = form(Login.class).bindFromRequest(); //--- error
if(loginForm.hasErrors()) {
return badRequest(login.render(loginForm));
} else {
session("email", loginForm.get().email);
return redirect(
routes.Application.index()
);
}
}
}
我理解它是與在登錄級的驗證功能,因爲當我刪除調用用戶。在驗證函數中驗證它的工作原理沒有錯誤。但我無法弄清楚。
用戶類是作爲 -
@Entity
public class User extends Model
{
@Id
@Constraints.Required
@Formats.NonEmpty
public String userId;
@OneToOne(cascade=CascadeType.PERSIST)
AccountDetails accDetails;
public static Model.Finder<String,User> find = new Model.Finder<String,User>(String.class, User.class);
// Authenticate the user details
public static User authenticate(String email, String password)
{
String tempId = AccountDetails.authenticate(email, password).userId;
return find.ref(tempId);
}
.. . . . . . .
}
和AccountDetails類 -
@Entity
public class AccountDetails extends Model
{
@Id
String userId;
@Constraints.Required
String emailId;
@Constraints.Required
String password;
public static Model.Finder<String,AccountDetails> find =
new Model.Finder<String,AccountDetails>(String.class, AccountDetails.class);
public static AccountDetails authenticate(String email, String password)
{
return find.where()
.eq("email", email)
.eq("password", password)
.findUnique();
}
}
任何幫助,將不勝感激。
非常感謝。
沒有導入聲明,沒有異常堆棧跟蹤,碎片代碼。除了你已經處理了這樣的問題之外,回答這個問題是相當頑固的。 –