2016-03-09 26 views
0

在開發Java中的AuditLogView時,我試圖通過「對象:www.test.com」進行過濾。我如何在下面添加一個過濾器對象?SL中的AuditLogView

com.softlayer.api.service.event.Log.Service eventLogService = 

com.softlayer.api.service.event.Log.service(client);

eventLogService.setResultLimit(new ResultLimit(0,50)); 
    Filter filter = new Filter(); 
    filter.addFilter("label").addProperty("name","???"); 
    eventLogService.addFilter(filter); 

    List<Log> a = eventLogService.getAllObjects(); 

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