我正在研究一個基於PHP-Mysql的網站,該網站有一些要顯示的大型列表(例如產品列表)。現在爲了方便用戶,我必須將其分解到頁面。所以我已經使用PHP添加了分頁。現在,每次點擊頁碼時都會刷新頁面。因此,我有一個使用PHP/MySQL的基礎,並且想要添加Ajax/jquery以避免不必要的頁面刷新 。如何將分頁添加到現有的代碼中? 這裏是供參考的php代碼。將jquery添加到基於php mysql的分頁
<div class="flt width710">
<div style="margin-top:10px;" class="flt mapnewalert"> <?php //echo ucfirst($_SESSION['$city']) ?></div>
<div style="float:right" id="toppagesel">
<?php
echo $pages->display_pages();
echo $pages->display_items_per_page();
//echo "<span class=\"\">".$pages->display_jump_menu()."</span>";
$query = "SELECT * from properties,locality,cities where properties.city_id='".$_SESSION['$cityId']."' and properties.locality_id=locality.locality_id and properties.city_id=cities.city_id $pages->limit";
$result = mysql_query($query) or die(mysql_error());
//$getProperty = $propertyDetails->getPropertyDetailsByCityIdPaginate($_SESSION['$cityId'],$limit);
?>
<?php //echo $pages->display_pages(); ?><?php //echo $pages->display_items_per_page();?>
</div>
</div>
而且分頁類:
class Paginator{
var $items_per_page;
var $items_total;
var $current_page;
var $num_pages;
var $mid_range;
var $low;
var $limit;
var $return;
var $default_ipp;
var $querystring;
var $ipp_array;
function Paginator()
{
$this->current_page = 1;
$this->mid_range = 2;
$this->ipp_array = array(2,4,6,8,'All');
$this->items_per_page = (!empty($_GET['ipp'])) ? $_GET['ipp']:$this->default_ipp;
}
function paginate()
{
if(!isset($this->default_ipp)) $this->default_ipp=2;
if($_GET['ipp'] == 'All')
{
$this->num_pages = 1;
// $this->items_per_page = $this->default_ipp;
}
else
{
if(!is_numeric($this->items_per_page) OR $this->items_per_page <= 0) $this->items_per_page = $this->default_ipp;
$this->num_pages = ceil($this->items_total/$this->items_per_page);
}
$this->current_page = (isset($_GET['page'])) ? (int) $_GET['page'] : 1 ; // must be numeric > 0
$prev_page = $this->current_page-1;
$next_page = $this->current_page+1;
if($_GET)
{
$args = explode("&",$_SERVER['QUERY_STRING']);
foreach($args as $arg)
{
$keyval = explode("=",$arg);
if($keyval[0] != "page" And $keyval[0] != "ipp") $this->querystring .= "&" . $arg;
}
}
if($_POST)
{
foreach($_POST as $key=>$val)
{
if($key != "page" And $key != "ipp") $this->querystring .= "&$key=$val";
}
}
if($this->num_pages > 4)
{
$this->return = ($this->current_page > 1 And $this->items_total >= 10) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$prev_page&ipp=$this->items_per_page$this->querystring\">« Previous</a> ":"<span class=\"inactive\" href=\"#\">« Previous</span> ";
$this->start_range = $this->current_page - floor($this->mid_range/2);
$this->end_range = $this->current_page + floor($this->mid_range/2);
if($this->start_range <= 0)
{
$this->end_range += abs($this->start_range)+1;
$this->start_range = 1;
}
if($this->end_range > $this->num_pages)
{
$this->start_range -= $this->end_range-$this->num_pages;
$this->end_range = $this->num_pages;
}
$this->range = range($this->start_range,$this->end_range);
for($i=1;$i<=$this->num_pages;$i++)
{
if($this->range[0] > 2 And $i == $this->range[0]) $this->return .= " ... ";
// loop through all pages. if first, last, or in range, display
if($i==1 Or $i==$this->num_pages Or in_array($i,$this->range))
{
$this->return .= ($i == $this->current_page And $_GET['page'] != 'All') ? "<a title=\"Go to page $i of $this->num_pages\" class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" title=\"Go to page $i of $this->num_pages\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
}
if($this->range[$this->mid_range-1] < $this->num_pages-1 And $i == $this->range[$this->mid_range-1]) $this->return .= " ... ";
}
$this->return .= (($this->current_page < $this->num_pages And $this->items_total >= 10) And ($_GET['page'] != 'All') And $this->current_page > 0) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$next_page&ipp=$this->items_per_page$this->querystring\">Next »</a>\n":"<span class=\"inactive\" href=\"#\">» Next</span>\n";
$this->return .= ($_GET['page'] == 'All') ? "<a class=\"current\" style=\"margin-left:10px\" href=\"#\">All</a> \n":"<a class=\"paginate\" style=\"margin-left:10px\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
}
else
{
for($i=1;$i<=$this->num_pages;$i++)
{
$this->return .= ($i == $this->current_page) ? "<a class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
}
$this->return .= "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
}
$this->low = ($this->current_page <= 0) ? 0:($this->current_page-1) * $this->items_per_page;
if($this->current_page <= 0) $this->items_per_page = 0;
$this->limit = ($_GET['ipp'] == 'All') ? "":" LIMIT $this->low,$this->items_per_page";
}
}
我怎樣才能實現呢?我提到其他線程並嘗試,但不能讓它在我context.I工作是新手阿賈克斯的jQuery部分很抱歉,如果它是一項簡單的任務! :P
PS:這是可能在當前的情況下,還是我必須對我的分頁類和php代碼進行更改。請把它放在一些燈!
感謝
非常感謝您的及時答覆,但我想的東西,符合上面的代碼或我將不得不重新審視logic.Can't我只是用新更換的div一個使用ajax?類似的建議在這裏,但我無法得到它的工作 - http://stackoverflow.com/questions/10755118/how-to-add-ajax-on-existing-php-mysql-based-pagination – KillABug