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拖動元素的智能參考線我一直在尋找一個可拖動的元素智能導遊，發現一個不錯的劇本在這裏 - https://stackoverflow.com/a/22062111工作不正常
它可以正常使用，直到我改變了結構的位。 指南是顯示不正確，如果包裝對齊顯示：inline-block的或浮動：左
我創建了一個小提琴在這裏 - http://jsfiddle.net/A6CpP/110/
$.ui.plugin.add("draggable", "smartguides", {
start: function(event, ui) {
var i = $(this).data("draggable");
console.log(i);
var o = i.options;
i.elements = [];
$(o.smartguides.constructor != String ? (o.smartguides.items || ':data(draggable)') : o.smartguides).each(function() {
var $t = $(this); var $o = $t.offset();
if(this != i.element[0]) i.elements.push({
item: this,
width: $t.outerWidth(), height: $t.outerHeight(),
top: $o.top, left: $o.left
});
});
},
stop: function(event, ui) {
$(".objectx").css({"display":"none"});
$(".objecty").css({"display":"none"});
},
drag: function(event, ui) {
var inst = $(this).data("draggable"), o = inst.options;
var d = o.tolerance;
$(".objectx").css({"display":"none"});
$(".objecty").css({"display":"none"});
var x1 = ui.offset.left, x2 = x1 + inst.helperProportions.width,
y1 = ui.offset.top, y2 = y1 + inst.helperProportions.height,
xc = (x1 + x2)/2, yc = (y1 + y2)/2;
for (var i = inst.elements.length - 1; i >= 0; i--){
var l = inst.elements[i].left, r = l + inst.elements[i].width,
t = inst.elements[i].top, b = t + inst.elements[i].height,
hc = (l + r)/2, vc = (t + b)/2;
var ls = Math.abs(l - x2) <= d;
var rs = Math.abs(r - x1) <= d;
var ts = Math.abs(t - y2) <= d;
var bs = Math.abs(b - y1) <= d;
var hs = Math.abs(hc - xc) <= d;
var vs = Math.abs(vc - yc) <= d;
if(ls) {
ui.position.left = inst._convertPositionTo("relative", { top: 0, left: l - inst.helperProportions.width }).left - inst.margins.left;
$(".objectx").css({"left":l-d-4,"display":"block"});
}
if(rs) {
ui.position.left = inst._convertPositionTo("relative", { top: 0, left: r }).left - inst.margins.left;
$(".objectx").css({"left":r-d-4,"display":"block"});
}
if(ts) {
ui.position.top = inst._convertPositionTo("relative", { top: t - inst.helperProportions.height, left: 0 }).top - inst.margins.top;
$(".objecty").css({"top":t-d-4,"display":"block"});
}
if(bs) {
ui.position.top = inst._convertPositionTo("relative", { top: b, left: 0 }).top - inst.margins.top;
$(".objecty").css({"top":b-d-4,"display":"block"});
}
if(hs) {
ui.position.left = inst._convertPositionTo("relative", { top: 0, left: hc - inst.helperProportions.width/2 }).left - inst.margins.left;
$(".objectx").css({"left":hc-d-4,"display":"block"});
}
if(vs) {
ui.position.top = inst._convertPositionTo("relative", { top: vc - inst.helperProportions.height/2, left: 0 }).top - inst.margins.top;
$(".objecty").css({"top":vc-d-4,"display":"block"});
}
};
}
});
$('.other-objects').draggable({
containment: 'parent',
smartguides:".other-objects",
tolerance:5
});