IF語句不能在PHP

驗證我有一個頁面上此PHP腳本這需要從變量輸入字段：IF語句不能在PHP

if($fname <> "" and $lname <> "" and $ydept <> "") { 
    if ($percentage >= "85") { 
     mail ($myEmail, $mailSubject, $msgBody, $header); 
     mail ($userEmail, $sentMailSubject, $sentMailBody, $sentHeader); 
     $filename = "blah.txt"; #Must CHMOD to 666, set folder to 777 
     $text = "\n" . str_pad($fname, 25) . "" . str_pad($lname, 25) . "" . str_pad($empID, 15) . "" . str_pad($doh, 15) . ""; 

     $fp = fopen ($filename, "a"); # a = append to the file. w = write to the file (create new if doesn't exist) 
     if ($fp) { 
      fwrite ($fp, $text); 
      fclose ($fp); 
      #echo ("File written"); 
     } 
     else { 
      #echo ("File was not written"); 
     } 
     header ("Location: yes.php?fname=$fname&type=$type"); 
    } 
    else { 
     header ("Location: didnotpass.php?percent=$percentage&type=$type"); 
    } 
} 
else { 
    header ("Location: empty.php?type=$type"); 
}

而且didnotpass.php腳本是：

<?php 
if (isset($_GET['type']) && isset($_GET['percentage'])) { 
    $percent = trim(strip_tags(stripslashes($_GET['percent']))); 
    $type = trim(strip_tags(stripslashes($_GET['type']))); 

    if ($type == "Clinical") { 
?> 
The Certificate of Attendance has been completed yet, but your score of $percent% is less then the passing score of 85%.<br><br> 
Please <b><a href="C.php">Click Here</a></b> to retake the certification. 
<?php 
    } 
    else { 
?> 
The Certificate of Attendance has been completed yet, but your score of $percent% is less then the passing score of 85%.<br><br> 
Please <b><a href="nonC.php">Click Here</a></b> to retake the certification. 
<?php 
    } 
} 
else { 
?> 
Please <b><a href="start.php">Go To Certification Homepage</a></b> to start the certification. 
<?php 
} 
?>

我的問題具有是否得分是85％或不是，它進入最後一條語句：

Please <b><a href="start.php">Go To Certification Homepage</a></b> to start the certification.

是我的IF語句correc T：

if ($percentage >= "85")

我想這是正常工作，因爲它被路由到正確的頁面，但在didnotpass.php的if/else語句無法正常工作。任何人都可以幫我修復它？

來源

2013-03-11 Si8

這似乎很容易檢查：在'if'條件給你之前'var_dump（$ percent）;'是什麼，你爲什麼要引用nu MBER？ – jeroen 2013-03-11 21:24:06

我的nopass.php網址如下所示：http://www.imed.com/sc/nopass.php?percent=38&type=Clinical – Si8 2013-03-11 21:28:43

你知道，這並不是說這可以解決你的問題，但它可能是一個壞主意在數字周圍使用引號。只要做'85'不加引號。 – Mike 2014-04-03 00:52:53

我認爲正在發生的事情是，percent的查詢字符串參數並不一致：

if (isset($_GET['type']) && isset($_GET['percentage'])) { 
    $percent = trim(strip_tags(stripslashes($_GET['percent']))); 
    $type = trim(strip_tags(stripslashes($_GET['type'])));

應該

if (isset($_GET['type']) && isset($_GET['percent'])) { 
    $percent = trim(strip_tags(stripslashes($_GET['percent']))); 
    $type = trim(strip_tags(stripslashes($_GET['type'])));

的if語句是指$_GET['percentage']而不是$_GET['percent']

來源

2013-03-11 21:27:44

，我知道我錯過了某個地方！謝謝JLC。問題修復了！ – Si8 2013-03-11 21:33:56

if ($percentage >= "85")

應該是：

if ($percentage >= 85)

不能圍繞着一些報價，然後指望它評估爲> =。它會把它當作一個字符串。您可能需要將其解析爲一個整數，具體取決於它是什麼類型。

來源

2013-03-11 21:24:53

謝謝。你的建議只是將比較字符串固定爲整數，但JLC的固定IF語句問題的比例爲 – Si8 2013-03-11 21:33:24

IF語句不能在PHP

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