PHP JSON請求

Question

您好我想使JSON請求一個API，但我不知道如何，因爲我從來沒有工作過的類似的東西。如果有人能幫助我，我會很感激。

下面是我需要請求：

請求負載：

{ 
    "sessionId": "1234567890", 
    "availabilityRequest": { 
     "checkInDate": "29042014", 
     "checkOutDate": "", 
     "noRooms": 1, 
     "noNights": 1, 
     "userType": "leisure", 
     "rateType": "standard", 
     "roomPreference": [ 
      { 
       "noAdult": 1, 
       "noChild": 0 
      } 
     ], 
     "siteCode": [ 
      "GB0758", 
      "GB0746", 
      "GB0738", 
      "GB0755", 
      "GB0742" 
     ], 
     "includeDisabled": "F" 
    } 
} 

這是我做了什麼，但我得到的錯誤Array ([error] => Array ([code] => 4007 [message] => Invalid JSON POST data (unable to decode):))

 $postData = '{ 
       "sessionId":"1234567890", 
       "availabilityRequest": 
       { 
        "checkInDate": "29042014", 
        "checkOutDate": "", 
        "noRooms": 1, 
        "noNights": 1, 
        "userType": "leisure", 
        "rateType": "standard", 
        "roomPreference": 
         [ 
          { "noAdult":1, "noChild":0 } 
         ], 
        "siteCode": 
         [ 
         "GB0758","GB0746","GB0738","GB0755","GB0742" 
         ], 
        "includeDisabled":"F" 
       } 
      }'; 

     $ch = curl_init($url); 
     curl_setopt_array($ch, array(
     CURLOPT_POST => TRUE, 
     CURLOPT_RETURNTRANSFER => TRUE, 
     CURLOPT_POSTFIELDS => $postData)); 

     curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 

     // Send the request 
     $response = curl_exec($ch); 

     // Check for errors 
     if($response === FALSE){ 
      die(curl_error($ch)); 
     } 

     // Decode the response 
     $responseData = json_decode($response, TRUE); 

     // Print the date from the response 
     print_r($responseData); 

我會真的很感激有人可以幫助我。謝謝

Answer 1

我真的不能測試這個，因爲我沒有URL來測試它，但你可以嘗試設置一個頭。

curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json', 'Content-Length: ' . strlen($postData))); 

Answer 2

您的JSON無效。使用工具如http://jsonlint.com/

您應該添加的其他}到年底將其關閉驗證。那麼你將有一個有效的JSON。