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我是Symfony2的新手,所以請幫我解決它。有實體報告和實體組織。symfony2:無法堅持實體並插入數據庫
報告映射的樣子:
<entity name="Acme\ReportsBundle\Entity\Report" table="reports_report">
<lifecycle-callbacks>
<lifecycle-callback type="prePersist" method="setCreatedAt"/>
<lifecycle-callback type="prePersist" method="setUpdatedAt"/>
</lifecycle-callbacks>
<many-to-one field="organization" target-entity="Acme\OrganizationBundle\Entity\Organization" inversed-by="reports">
<join-column name="organization_id" referenced-column-name="id" />
</many-to-one>
<many-to-one field="year" target-entity="Acme\ReportsBundle\Entity\Year" inversed-by="reports">
<join-column name="year_id" referenced-column-name="id" />
</many-to-one>
<id name="id" type="integer" column="id">
<generator strategy="IDENTITY"/>
</id>
<field name="organization_id" type="integer" lenght="11" nullable="false" />
<field name="year_id" type="integer" lenght="11" nullable="false" />
<field name="status" type="smallint" nullable="true" />
<field name="user_created" type="integer" lenght="11" nullable="false" />
<field name="user_updated" type="integer" lenght="11" nullable="false" />
<field name="created_at" type="datetime" nullable="false" />
<field name="updated_at" type="datetime" nullable="false" />
</entity>
,並組織部分:
/**
* @ORM\OneToMany(targetEntity="Acme\ReportsBundle\Entity\Report", mappedBy="organizations")
*
*/
protected $reports;
/**
* Constructor
*/
public function __construct()
{
$this->users = new \Doctrine\Common\Collections\ArrayCollection();
$this->reports = new \Doctrine\Common\Collections\ArrayCollection();
}
我嘗試使用構造函數設置報告屬性: 的Acme \ ReportsBundle \實體\報告
public function __construct(\Acme\OrganizationBundle\Entity\Organization $organization, \Acme\ReportsBundle\Entity\Year $year, \Application\Sonata\UserBundle\Entity\User $user)
{
$this->organization_id = $organization->getId();
$this->year_id = $year->getId();
$this->user_created = $user->getId();
$this->user_updated = $user->getId();
}
最後控制器 Acme/ReportsBundle /控制器/ DefaultController:
public function indexCreate()
{
$organization = $this->getDoctrine()
->getRepository('AcmeOrganizationBundle:Organization')
->find(2);
$year = $this->getDoctrine()
->getRepository('AcmeReportsBundle:Year')
->find(888);
$user = $this->getDoctrine()
->getRepository('ApplicationSonataUserBundle:User')
->find(20);
$report = new Report($organization, $year, $user);
// var_dump shows that all properties were set
$em = $this->getDoctrine()->getManager();
$em->persist($report);
$em->flush();
}
所以,參觀這條路線,我得到:
An exception occurred while executing 'INSERT INTO reports_report (organization_id, year_id, status, user_created, user_updated, created_at, updated_at) VALUES (?, ?, ?, ?, ?, ?, ?)' with params [null, null, null, 20, 20, "2014-09-21 15:07:41", "2014-09-21 15:07:41"]:
SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'organization_id' cannot be null
那麼,什麼是錯與性能whitch使用構造函數設置?爲什麼user_id是持久的,但是organization_id和year_id不是?