CakePHP加密URL

Question

我想加密在CakePHP中傳遞的URL。我跟着這篇文章（http://bakery.cakephp.org/articles/yuri.salame/2008/07/15/encrypting-urls#），它不起作用。我知道這是一篇舊文章。我使用CakePHP的2.x的

這裏顯示的錯誤：

Notice (8): Undefined index: url [APP/webroot/index.php, line 108] 
Warning (4096): Argument 1 passed to Dispatcher::dispatch() must be an instance of CakeRequest, null given, called in /home/xxx/domains/xxx.com/public_html/xxx/v3/app/webroot/index.php on line 110 and defined [CORE/Cake/Routing/Dispatcher.php, line 140] 
Warning (4096): Argument 2 passed to Dispatcher::dispatch() must be an instance of CakeResponse, none given, called in /home/xxx/domains/xxx.com/public_html/xxx/v3/app/webroot/index.php on line 110 and defined [CORE/Cake/Routing/Dispatcher.php, line 140] 
Notice (8): Trying to get property of non-object [CORE/Cake/Routing/Filter/AssetDispatcher.php, line 45] 

我應用程序/ Web根目錄/的index.php是（我只顯示最後一個部分）：

App::uses('Dispatcher', 'Routing'); 

$url = do_decrypt($_REQUEST["url"]); 
$Dispatcher = new Dispatcher(); 
$Dispatcher->dispatch($url); 

$Dispatcher = new Dispatcher(); 
$Dispatcher->dispatch(
    new CakeRequest(), 
    new CakeResponse() 
); 

Answer 1

CakePHP隨附的.htaccess文件已在CakePHP 2.x中進行了更改。它不再設置url變量，因此它在$_REQUEST中不可用。相反，您可以使用$_SERVER['REQUEST_URI']來獲取網址。這個URL然後必須被傳遞給構造函數CakeRequest。因此，您的代碼將如下所示：

App::uses('Dispatcher', 'Routing'); 

$url = do_decrypt($_SERVER["REQUEST_URI"]); 
$Dispatcher = new Dispatcher(); 
$Dispatcher->dispatch(
    new CakeRequest($url), 
    new CakeResponse() 
);