我想創建一個具有以下結構的表:
ROW1 datacolumn1 datacolumn2 datacolumn2
SubRow1 datacolumn1 datacolumn2 datacolumn2
SubRow2 datacolumn1 datacolumn2 datacolumn2
SubRow3 datacolumn1 datacolumn2 datacolumn2
展開/摺疊表中的行與嵌套行
我想讓這些子箭頭在點擊時展開/摺疊。我似乎不能使它與表格一起工作。我知道列表將是更好的選擇,但表格更容易維護。
<tbody>
<tr class="row1 head1">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row1 head2 closed">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row1 head3">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row1 head4">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row1 head5">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row2 head1">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row2 head4">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr class="row2 head5">
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr>
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
<tr>
<td>Cash and Equivalents</td>
<td>000,000</td>
<td>000,000</td>
</tr>
</tbody>
上排一下,我調用下面的函數:
holdingsTree: function(that){
var stack = '',
classes = ba.splitClasses(that.attr('class')),
nextRow = ba.getClassNumber(classes[1], "head");
if (that.next().hasClass('head'+nextRow)){
if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
} else if (that.next().hasClass(classes[0])){
stack = that.nextUntil('.head1');
$.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow))){ $(this).show().addClass('open').removeClass('closed'); } });
}
} else if (that.next().hasClass('head'+ (nextRow+1))){
if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
} else if (that.next().hasClass(classes[0])){
stack = that.nextUntil('.head1');
$.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+1))){ $(this).show().addClass('open').removeClass('closed'); } });
}
} else if (that.next().hasClass('head'+ (nextRow+2))){
if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
return;
} else if (that.next().hasClass(classes[0])){
stack = that.nextUntil('.head'+ (nextRow+3));
$.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+2))){ $(this).show().addClass('open').removeClass('closed'); } });
//stack.find('.head'+(nextRow+2)).show().addClass('open').removeClass('closed');
}
} else if (that.next().hasClass('head'+ (nextRow+3))){
if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
} else if (that.next().hasClass(classes[0])){
stack = that.nextUntil('.head1');
$.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+3))){ $(this).show().addClass('open').removeClass('closed'); } });
}
} else if (that.next().hasClass('head'+ (nextRow+4))){
if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
} else if (that.next().hasClass(classes[0])){
that.nextUntil('.head1').show().addClass('open').removeClass('closed');
}
}
},
splitClasses: function(names){
var names = names.split(' ');
return names;
},
getClassNumber: function(name, pretext){
var result = name.split(pretext);
console.log(parseInt(result[1]) + 1);
return parseInt(result[1]) + 1;
}
它非常糟糕。我知道。 :)
除了切換,您可以使用fadeToggle()或slideToggle()來獲得不同的效果。 – Angel 2012-07-20 07:38:19
只處理單層嵌套。我有多個嵌套級別照顧.. – amit 2012-07-22 22:04:26
更新了我的答案在任何級別上的工作。 – Angel 2012-07-23 07:12:34