檢查空陣列和刪除空陣列

Question

我有100個值在數組中，需要檢查前十個值不爲空，所有元素應該是相同的計數，如果不取消設置值，我使用「|」用於梳理所有的值，

我有所有的價值與「|」下面是即時通訊使用im沒有得到最終的結果需要，finalvalues下面給出的功能，你可以請幫忙解決這個問題

finalvalues =array(
    "3" =>"Education|Category|Roles|Industry|Address|Email|Phone|Mobile", 
    "4" => "Bsc|computer|SE|Computers||test@test.com|123123132|123234234234" 
); 

$values = array(
     "0"=> "Computer Student History", 
     "1"=> "Computer Student History", 
     "2"=> "Computer Student History|batch number", 
     "3" => "| | | | | | | | | | | | | | | | ", 
     "4" => "Education|Category|Roles|Industry|Address|Email|Phone|Mobile", 
     "5" => "Bsc|computer|SE|Computers||test@test.com|123123132|123234234234" 
); 



$newVal = array(); 
    foreach ($values as $key => $val) { //$values it is.. 
    $prevalues = explode('|', $val); 
    $finalvalue = array_empty($prevalues ,$full_null=true); 
     if($finalvalue == 1){ 
     unset($prevalues); //why?? 
    }else{ 
    $vales = implode('|', $prevalues); 
    $newVal[$key] = $vales; //use $key, to preserve the keys here.. 
    } 
    } 
    print_r($newVal); //output 

    function array_empty($ary, $full_null=false){ 

    unset($prevKey); 
    $count = array(); 
    $null_count = 0; 
    $ary_count = count($ary); 
    if ($ary_count == 1) //this means there was no '|', hence no split. 
    return 1; 

    foreach($array_keys($ary) as $value){ 
    //  echo $value; 
//trying check if first value is less then second value unset array similar second is less then third value unset second .. so the all the array values is same count 

$count[$value] = count($ary[$value]); 
    if (isset($prevKey) && $count[$prevKey] !== $count[$value]) { 
    //unset($array[$prevKey]); 
    return 1; 
    } 

    if($value == NULL || trim($value) == ""){ // trim(..) was what you wanted. 
     $null_count++; 
    } 
    } 

if($full_null == true){ 
    if($null_count == $ary_count){ 
     return 1; 
    }else{ 
     return 0; 
    } 
    } 
    } 

Answer 1

這裏有一些簡單得多，沒有瘋狂的方式

PHP 5.3+

$final = array_filter(
    $values, 
    function($v){ 
     return 
      preg_replace('~\s*\|\s*~', '', $v) && 
      count(explode('|', $v)) === 8; 
    } 
); 

PHP < 5.3

此編輯$值陣列直接

foreach($values as $k => $value) { 
    if (preg_replace('~\s*\|\s*~', '', $value) == '' || count(explode('|', $value)) !== 8) { 
     unset($values[$k]); 
    } 
} 

Answer 2

這會幫助你（其內部註釋）：

$newVal = array(); 
foreach ($values as $key => $val) { //$values it is.. 
    $prevalues = explode('|', $val); 
    $finalvalue = array_empty($prevalues ,$full_null=true); 
    if($finalvalue == 1){ 
     unset($prevalues); //why?? 
    }else{ 
     $vales = implode('|', $prevalues); 
     $newVal[$key] = $vales; //use $key, to preserve the keys here.. 
    } 
} 
print_r($newVal); //output 

function array_empty($ary, $full_null=false){ 
    $null_count = 0; 
    $ary_count = count($ary); 
    if ($ary_count == 1) //this means there was no '|', hence no split. 
     return 1; 

    foreach($ary as $value){ 
    //  echo $value; 
     if($value == NULL || trim($value) == ""){ // trim(..) was what you wanted. 
      $null_count++; 
     } 
    } 

    if($full_null == true){ 
     if($null_count == $ary_count){ 
      return 1; 
     }else{ 
      return 0; 
     } 
    } 
}