我正在進行在線測試。有10個級別。問題是從數據庫中挑選出來的,如果答案是正確的,那麼它會更新清除該特定用戶的級別,並在同一頁面上顯示下一個問題。如果答案正確,將代碼重定向到其他頁面
但是我想要將頁面定向到另一個頁面,如果答案正確的話,它的URL位於數據庫中並且像上面那樣更新用戶的級別號碼。 我知道如何在同一頁面顯示問題,但不知道如何正確重定向。
下面是在同一頁面顯示問題的簡單測試代碼。
<?php
session_start();
if(!isset($_SESSION['myusername'])){
header("location:index.php?unreg=1");
}
else {
$myuser = $_SESSION["myusername"];
$mypass = $_SESSION["mypassword"];
$host="localhost"; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name="members"; // Table name
$tbl_name2="quiz"; // Table name 2
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
if(isset($_POST['qno']))
{
$sql3="SELECT * FROM $tbl_name2 WHERE id='".$_POST['qno']."'";
$result3=mysql_query($sql3);
$disp3=mysql_fetch_assoc($result3);
$sql4="SELECT * FROM $tbl_name WHERE username='$myuser' and password='$mypass'";
$result4=mysql_query($sql4);
$disp4=mysql_fetch_assoc($result4);
if($disp3['Answer']==$_POST['Answer'])
{
$sql5 ="UPDATE $tbl_name SET level_crossed='".($disp4
['level_crossed'] +1)."', Score=' $disp4['Score']+1)."' WHERE
username='$myuser' and password='$mypass'";
$result5=mysql_query($sql5);
}
else {
$sql5="UPDATE $tbl_name SET level_crossed='".($disp4['level_crossed']+1).
"' WHERE username='$myuser' and password='$mypass'";
$result5=mysql_query($sql5);
}
}
$sql="SELECT * FROM $tbl_name WHERE username='$myuser' and password='$mypass'";
$result=mysql_query($sql);
$disp=mysql_fetch_assoc($result);
echo " ".$disp['level_crossed']." ";
$sql7="SELECT * FROM $tbl_name2 WHERE id='".($disp['level_crossed']+1)."'";
$result7=mysql_query($sql7);
$disp2=mysql_fetch_assoc($result7);
?>
<br>
<?php
echo "Q.)".$disp2['Question']." ";
?>
<br>
<form name="quizq" action="quiz1.php" method="post" >
<input name="qno" type="hidden" value="<?php echo $disp['level_crossed']+1; ?>" />
<input type="radio" name="Answer" value="<?php echo $disp2['Option1'];>" /><?
php echo $disp2['Option1']; ?><br>
<input type="radio" name="Answer" value="<?php echo $disp2['Option2']; ?>" />
<?php echo $disp2['Option2']; ?><br>
<input type="radio" name="Answer" value="<?php echo $disp2['Option3']; ?>" />
<?php echo $disp2['Option3']; ?><br>
<input type="radio" name="Answer" value="<?php echo $disp2['Option4']; ?>" />
<?php echo $disp2['Option4']; ?><br>
<input type="submit" value="Submit Answer" />
</form>
<br><br>
<a href="logout.php">Logout</a>
<?php
}
?>
是否有打算進行一些代碼上市? – Nerdwood
不管怎樣,我們不需要看到它 –
Mysql_已被棄用,請使用PDO或mysqli代替 – Furry