運行域名的列表，以獲取IP地址

Question

我想通過獲取URL

for url in list: 

Host = "host %s" % url 

IPADDRESS = subprocess.check_output(HOST, shell=True) 

print IPADDRESS 

Answer 1

的URL列表中運行 「主機domain.com」：

os.system("host %s | grep 'has address' | sort -u" % (url)) 

Answer 2

enter code here 
#!/usr/bin/python 
import subprocess 
list = ("/root/cisco/indexlist.txt","r") 
for hostname in list: 
p1 = subprocess.Popen(['host', hostname],stdout=subprocess.PIPE) 
p2 = subprocess.Popen(['grep', 'IP ADDRESS'], stdin=p1.stdout, stdout=subprocess.PIPE) 
p3 = subprocess.Popen(['sort','-u'],stdin=p2.stdout, stdout=subprocess.PIPE) 
print (p3.communicate()[0])