通過python發佈Post有問題

Question

我遇到了一些麻煩。我正在嘗試發送POST並嘗試跟蹤文檔，但我似乎無法正確理解。

在GitHub上：https://github.com/trtmn/Python

引入請求的歡迎！

# Getting documentation from : 
#https://docs.python.org/2/howto/urllib2.html 
import urllib 
import urllib2 

url = 'https://hooks.slack.com/services/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' 
values = {"username": "webhookbot", "text": "This is posted to #general and comes from a bot named webhookbot.", "icon_emoji": ":ghost:"} 

data = urllib.urlencode(values) 
req = urllib2.Request(url, data) 
response = urllib2.urlopen(req) 
the_page = response.read() 

Answer 1

看起來像我需要將其字符串化爲JSON（我知道，但不知道如何）。感謝Tim G.的幫助。

因此，這裏的功能代碼：

import urllib2 
import json 

url = 'https://hooks.slack.com/services/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' 
values = {"username": "webhookbot", "text": "This is posted to #general and comes from a bot named webhookbot.", "icon_emoji": ":ghost:"} 

data = json.dumps(values) 
req = urllib2.Request(url, data) 
response = urllib2.urlopen(req) 
the_page = response.read() 

Answer 2

不知道這是否解決了問題，但如果我添加斜線到您的網址的結尾我收到答覆，當我執行你的代碼。

URL = 'https://hooks.slack.com/services/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/'

Answer 3

使用httplib的是後一種替代方案：

*進口httplib的

conn = httplib.HTTPSConnection(host) 
conn.request('POST',urI,request_body, headers)  
response = conn.getresponse() 
resp_status=response.status 
resp_reason=response.reason 
resp_body=response.read() 
conn.close()* 

看看這會有所幫助。