函數內的函數，數組，Julia

Question

我有第一個函數使用!我想在第二個函數中調用succrate和price的乘法，調用初始函數。什麼是語法？感謝

length_of_arrays = 101 

lower_limit = 0 
steps_per_unit = 1 

price1 = 10 

succrate1 = 5 
succrate2 = 7 

price = Array{Float64, 1}(101) 
succrate = Array{Float64, 2}(101,20)  


function modifyarrays!(length_of_arrays, price, lower_limit, steps_per_unit, succrate) 
for pr_A in 1:101 

price[pr_A] = lower_limit + ((pr_A-1)/steps_per_unit) 

    for d in 1:20 
    if price[pr_A] == price1 
     succrate[pr_A, d] = succrate1 
    else 
     succrate[pr_A, d] = succrate2 
    end 
    end 
end 

end 

modifyarrays!(101, price, 0, 1, succrate) 

Answer 1

function set_price_at!(price, pr_A, lower_limit, steps_per_unit) 
    price[pr_A] = lower_limit + ((pr_A-1)/steps_per_unit) 
    nothing 
end 

function set_succrate_at!(succrate, pr_A, price, succrate1, succrate2) 
    set_price_at!(price, pr_A, lower_limit, steps_per_unit) # You could call it here (1) 
    for d in 1:20 
     if price[pr_A] == price1 
      succrate[pr_A, d] = succrate1 
     else 
      succrate[pr_A, d] = succrate2 
     end 
    end 
end 

function modifyarrays!(length_of_arrays, price, lower_limit, steps_per_unit, succrate) 
    for pr_A in 1:101 
     # set_price_at!(price, pr_A, lower_limit, steps_per_unit) # or here (2) 
     set_succrate_at!(succrate, pr_A, price, succrate1, succrate2) 
    end 
end 

price = rand(Float64, (101,)) 
succrate = rand(Float64, (101,20)) 

modifyarrays!(101, price, 0, 1, succrate) 

我喜歡在調用函數（2）超過在稱之爲（1）。