我有這個數據幀叫做mydf
。我的下面的代碼繪製了Y軸效率圖的混合組合。我想要做的是將每個樣本組合(每條線)的X軸測量替換爲測量列表示的值。因此,對於efficiency1
,我希望它可以用measurement1
列中的值精確表示,而不是代碼中的一般1至7測量值,我希望對它們各自的測量列進行所有效率級別的測量。有人可以幫助我實現這個目標嗎?如何在R中正確繪製動態漸進繪圖
mydf<-structure(list(sample_A = structure(c(1L, 2L, 2L, 2L, 3L, 4L), .Label = c("2568",
"2669", "2670", "2671", "2946", "LPH-001-10_AK1", "LPH-001-12_AK2",
"LPH-001-9"), class = "factor"), sample_B = structure(c(1L, 2L,
3L, 4L, 3L, 4L), .Label = c("2568", "2669", "2670", "2671", "2946",
"LPH-001-10_AK1", "LPH-001-12_AK2", "LPH-001-9"), class = "factor"),
efficiency1 = c(1.02, 0.964, 0.415, 0.422, 0.98, 0.986),
efficiency2 = c(1, 0.944, 0.395, 0.402, 0.96, 0.966), efficiency3 = c(0.9,
0.844, 0.295, 0.302, 0.86, 0.866), efficiency4 = c(0.32,
0.264, -0.285, -0.278, 0.28, 0.286), efficiency5 = c(0.02,
-0.0360000000000001, -0.585, -0.578, -0.0200000000000001,
-0.0140000000000001), efficiency6 = c(0.12, 0.0639999999999999,
-0.485, -0.478, 0.08, 0.086), efficiency7 = c(0.02, -0.036,
-0.585, -0.578, -0.02, -0.014), measurement1 = c(1, 1.2,
1, 1.3, 1.3, 1), measurement2 = c(2, 2.1, 2, 2.2, 2.3, 2),
measurement3 = c(3, 3.1, 3, 3.2, 3.3, 3), measurement4 = c(4,
4.1, 4, 4.2, 4.3, 4.1), measurement5 = c(5.1, 5.1, 4, 4.2,
4.3, 4.1), measurement6 = c(5.1, 6.1, 6, 6.2, 6.3, 6.1),
measurement7 = c(7.1, 7.1, 7, 7.2, 6.3, 7.1)), .Names = c("sample_A",
"sample_B", "efficiency1", "efficiency2", "efficiency3", "efficiency4",
"efficiency5", "efficiency6", "efficiency7", "measurement1",
"measurement2", "measurement3", "measurement4", "measurement5",
"measurement6", "measurement7"), row.names = c(NA, 6L), class = "data.frame")
代碼,我有:
effCis <- grep('^efficiency',names(mydf));
xlim <- c(1,length(effCis));
ylim <- range(mydf[,effCis],na.rm=T);
ylim[1L] <- floor(ylim[1L]/0.1)*0.1;
ylim[2L] <- ceiling(ylim[2L]/0.1)*0.1;
xticks <- seq_along(effCis);
yticks <- seq(ylim[1L],ylim[2L],0.1);
plot(NA,xlim=xlim,ylim=ylim,xlab='measurement',ylab='efficiency',xaxs='i',yaxs='i',axes=F);
abline(v=xticks,col='lightgrey');
abline(h=yticks,col='lightgrey');
abline(h=0,lwd=2);
axis(1L,xticks,xticks,font=2L,cex.axis=0.7);
axis(2L,yticks,sprintf('%.1f',yticks),las=1L,font=2L,cex.axis=0.7);
hybrid.col <- data.frame(hybrid=seq_len(nrow(mydf)),col=c('red','green','blue','gold','cyan','magenta'),stringsAsFactors=F);
splineN <- 200L;
for (ri in seq_len(nrow(hybrid.col))) {
hybrid <- hybrid.col$hybrid[ri];
col <- hybrid.col$col[ri];
x <- xticks;
y <- c(as.matrix(mydf[hybrid,effCis]));
points(x,y,pch=16L,col=col,xpd=NA);
with(spline(x,y,splineN),{
lines(x,y,col=col,lwd=2,xpd=NA);
localwin <- which(x>2 & x<3);
tp <- which.min(abs(diff(y[localwin])));
if (length(tp)>0L) points(x[localwin[tp]],y[localwin[tp]],col=col,pch=4L);
localwin <- which(x>2 & x<5);
tp <- which.min(diff(y[localwin]));
if (length(tp)>0L) {
m <- diff(y[localwin[seq(tp,len=2L)]])/diff(x[localwin[seq(tp,len=2L)]]);
if (is.finite(m)) abline(y[localwin[tp]]-m*x[localwin[tp]],m,col=col,lty=2L);
};
});
};
製作'xticks'您的變量,你應該做的。 –
@RomanLuštrik我怎麼把相應的列,我有點困惑。你能拿出來嗎? – MAPK