繼承內部類Python3

Question

我需要的是這樣的

class Parent(object): 
    class Base(object): 
     def __init__(self, a, b): 
      self.a = a 
      self.b = b 


    class Derived(Base): 
     def __init__(self, a, b, c): 
      super(Derived,self).__init__(a, b) 
      self.c = c 

     def doit(): 
      pass 

parent = Parent() 
derived = parent.Derived(x,y,z) 
derived.doit() 

當我嘗試運行它，我得到這個以下錯誤：NameError: name 'Derived' is not defined

我的「衍生」的地方試圖與「基地」在super() - 沒有幫助

Answer 1

前綴「衍生」與「家長」，成功了。正如我已經評論過這個問題。這只是爲了試驗'派生'類。但我仍然想知道'派生類（Base）：'類是否正常（'Base'類沒有'Parent。'前綴）

class Parent(object): 
    class Base(object): 
     def __init__(self, a, b): 
      self.a = a 
      self.b = b 


    class Derived(Base): 
     def __init__(self, a, b, c): 
      super(Parent.Derived,self).__init__(a, b) 
      self.c = c 

     def doit(): 
      pass 

parent = Parent() 
derived = parent.Derived(x,y,z) 
derived.doit() 

Answer 2

類的繼承不會改變父類。在這種情況下，Parent類只包含原始的Base類，而不包含派生類。

您可以簡單地使用猴子打補丁來解決這個問題，

class Parent(object): 
    pass 


class Base(object): 
    def __init__(self, a, b): 
     self.a = a 
     self.b = b 


class Derived(Base): 
    def __init__(self, a, b, c): 
     super(Derived,self).__init__(a, b) 
     self.c = c 

    def doit(self): 
     pass 

Parent.Derived = Derived 

parent = Parent() 
x, y , z = 1, 1, 1 
derived = parent.Derived(x,y,z) 
derived.doit()