檢查輸入字符串是否有效日期或不在jQuery

Question

如何檢查字符串是否有效的日期？如果它是有效的，我想返回true否則爲false。字符串將如'01 -JUN-2012'

Answer 1

以下函數檢查（dd MMM yyyy）格式。沒有破折號（ - ）被接受。它可以幫助你或採取正則表達式的密切關注，以小修改..

function isDate(txtDate) 
{ 
    var currVal = txtDate; 
    if(currVal == '') 
     return false; 

    var rxDatePattern = /^((31(?!\(Feb(ruary)?|Apr(il)?|June?|(Sep(?=\b|t)t?|Nov)(ember)?)))|((30|29)(?!\ Feb(ruary)?))|(29(?=\ Feb(ruary)?\ (((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00)))))|(0?[1-9])|1\d|2[0-8])\ (Jan(uary)?|Feb(ruary)?|Ma(r(ch)?|y)|Apr(il)?|Ju((ly?)|(ne?))|Aug(ust)?|Oct(ober)?|(Sep(?=\b|t)t?|Nov|Dec)(ember)?)\ ((1[6-9]|[2-9]\d)\d{2})$/; //Declare Regex 
    var dtArray = currVal.match(rxDatePattern); // is format OK? 

    if (dtArray == null) 
     return false; 

    //Checks for dd MMM yyyy format. 

    dtMonth = dtArray[2]; 

    dtDay= dtArray[1]; 

    dtYear = dtArray[dtArray.length-2];  



    if (dtDay < 1 || dtDay> 31) 
     return false; 
    else if (dtMonth == 2) 
    { 
     var isleap = (dtYear % 4 == 0 && (dtYear % 100 != 0 || dtYear % 400 == 0)); 
     if (dtDay> 29 || (dtDay ==29 && !isleap)) 
       return false; 
    } 
    return true; 
} 

});​ 

工作演示上jsFiddle