有沒有辦法讓它,所以我可以排序通過一個ArrayList輸出最高的號碼與找到的最低號碼?我有辦法,現在是一個「shoppinglist」所設置的是這樣的:Java - 通過arraylist並輸出最高到最低的數字?
public void addToBag(String anyItem, int anyUnits, double anyCost){
int checkUnits = anyUnits;
double checkCost = anyCost;
if(checkUnits < 0 || checkCost < 0){
System.out.println("You must enter a value equal to or greater than 0!");
}else{
shoppingBag.add(new Item(anyItem, anyUnits, anyCost));
}
}
和輸出僅輸出列表
public void calculateSalesReceipt(){
System.out.println("Enter the sales tax percentage (ex. 0.08 for 8%) or type \"random\" for a random number: ");
double tax = keybd.nextDouble();
if(tax < 0){
System.out.println("You must enter a value equal to or greater than 0!");
}else{
getPricePreTax();
total = total;
taxCost = total * tax;
finaltotal = total + taxCost;
System.out.println("Sales Receipt");
System.out.println("-------------");
for(Item currentProduct : shoppingBag){
System.out.println(currentProduct.getName() + " - " + currentProduct.getUnits() + " units " + " - $" + currentProduct.getCost());
}
System.out.println("Total cost: $" + total);
System.out.println("Total tax: $" + taxCost);
System.out.println("Total cost with tax: $" + finaltotal);
System.out.println("Do you have any coupons? Enter \"yes\" or \"no\"");
String answer = keybd.next();
if(answer.equals("yes")){
applyCoupon();
}else if(answer.equals("no")){
System.out.println("Thank you!");
}else if(answer != "yes" || answer != "no"){
System.out.println("Thank you!");
}
System.out.println("Coupon discounts: $" + couponAmount);
System.out.println("Grand total: $" + (finaltotal-couponAmount));
}
}
謝謝!
編輯:
將這項工作?
public void getLargest(){
for(Item currentProduct : shoppingBag){
System.out.println(Collections.max());
}
}
好的,你能解決這個問題嗎?我在編輯它 – tekman22 2011-05-12 17:18:47
public void getLargest(){ for(Item currentProduct:shoppingBag){ System.out.println(Collections.max()); } } – tekman22 2011-05-12 17:18:59