一般Linq數據方法

Question

我想創建一個通用的方法，根據給定的參數，如：table，field1和field2從Linq獲取數據。

一個方法，將改爲使用這些2分特異性的人。例如：

public void DistributeCB(ComboBox cb) 
    { 
     BooksDBDataContext db = new BooksDBDataContext(); 
     Type T = db.GetType(); 

     //Authors table 
     var data =db.Authors.Select(author => new 
     { 
      Id = author.AuthorId, //field 1 
      Value = author.AuthorName //field 2 
     }); 
     cb.ValueMember = "Id"; 
     cb.DisplayMember = "Value"; 
     cb.DataSource = data; 
    } 

    public void DistributeCB2(ComboBox cb) 
    { 
     BooksDBDataContext db = new BooksDBDataContext(); 

     //Publishers table 
     var data = db.Publishers.Select(publisher => new 
     { 
      Id = publisher.PublishingId, //field 1 
      Value = publisher.PublishingName //field 2 
     }); 
     cb.ValueMember = "Id"; 
     cb.DisplayMember = "Value"; 
     cb.DataSource = data; 
    } 

Answer 1

好吧，如果你不介意傳遞實體作爲一個通用型的，而不是一個字符串參數，你可以嘗試：

對LINQ到實體：

public void Distribute<TEntity>(ComboBox cb, 
           DbContext db, 
           string valueField, 
           string displayField) 
         where TEntity : class 
{ 

    //Publishers table 
    var data = db.Set<TEntity>() as IEnumerable; 

    cb.ValueMember = valueField; 
    cb.DisplayMember = displayField; 
    cb.DataSource = data; 
} 

對LINQ到SQL：

public void Distribute<TEntity>(ComboBox cb, 
           DataContext db, 
           string valueField, 
           string displayField) 
         where TEntity : class 
{ 

    //Publishers table 
    var data = db.GetTable<TEntity>() as IEnumerable; 

    cb.ValueMember = valueField; 
    cb.DisplayMember = displayField; 
    cb.DataSource = data; 
} 

Answer 2

我嘗試一些東西，它的工作原理，但我敢肯定它的代碼：

public void Distribute<TEntity>(ComboBox cb, BooksDBDataContext db, string valueField, string displayField) 
        where TEntity : class 
    { 


     var data = db.GetTable<TEntity>(); 


     cb.ValueMember = valueField; 
     cb.DisplayMember = displayField; 
     cb.DataSource = data; 
    }