Laravel 5.4將json保存到數據庫

幫我保存json到db。表字段類型 - 文本。我有模型澆鑄陣列Laravel 5.4將json保存到數據庫

class Salesteam extends Model 
{ 
    protected $casts = [   
     'team_members' => 'array' 
    ]; 
}

我想要得到的JSON這樣{「指標」：「用戶id」}，並將其存儲到數據庫中。例子：

{"1":"7","2":"14","3":"25","4":"11"}

我有銷售組型號和「team_members」以dB爲單位列保存所有用戶ID屬於這個團隊。我的代碼通過ID查找團隊，獲取所有'team_members'屬性併爲該團隊添加新用戶。我希望以json格式存儲所有用戶並在添加新用戶標識時增加索引。

銷售組屬性：

"id" => 20 
"salesteam" => "Admin" 
"team_leader" => 0 
"invoice_target" => 884.0 
"invoice_forecast" => 235.0 
"team_members" => "[1,66,71]" 
"leads" => 0 
"quotations" => 0 
"opportunities" => 0 
"notes" => "" 
"user_id" => 1 
"created_at" => "2017-09-22 09:13:33" 
"updated_at" => "2017-09-22 13:10:25" 
"deleted_at" => null

代碼來添加新用戶團隊：

$salesTeam = $this->model->find($salesTeamId); 
$teamMembers = $salesTeam->team_members; 
$teamMembers[] = $userId; 
$salesTeam->team_members = $teamMembers; 
$salesTeam->save();

但它存儲到數據庫陣列並沒有指數

"team_members" => "[1,34,56]"

從Laravel文檔 - Array & JSON Casting 「數組將自動被序列化回JSON進行存儲」

我在哪裏錯了？

來源

2017-09-22 tosky

你的問題不太清楚，請補充更具體的細節？你的代碼做了什麼？並在哪個變量或哪行代碼中獲得哪個輸出？ – C2486

在保存之前將它編碼爲JSON？ –

，如果你得到這個"[1,34,56]"只是做json_decode($team_members)

，你就會有這樣的：

array:3 [▼ 
    0 => 1 
    1 => 34 
    2 => 56 
]

來源

2017-09-22 13:00:31 Onix

爲了使JSON字符串這樣

{"1":"7","2":"14","3":"25","4":"11"}

在php，你必須通過關鍵，當你推動元素到數組。例如

$teamMembers = []; 
$teamMembers['1'] = 7; 
$teamMembers['2'] = 14; 
...

如果你不讓它的associative array，php將轉換爲JSON字符串時，認爲這是JSON數組..

提示：您可以通過只需一個鍵，它會工作太。例如

$test = [1, 2, 3, 4, 5, 6]; 

$test['10'] = 56; 

echo json_encode($test);

輸出：

"{"0":1,"1":2,"2":3,"3":4,"4":5,"5":6,"10":56}"

PHP-Reference

來源

2017-09-22 13:05:09 rummykhan

簡單的解決方案

$books = App\Book::all(); 
$user->books = $books->toJson(); 
$user->save(); //example: userid -> 2 

$user = App\User::find(2); 
$userBooks = json_decode($user->books, true); // to generate object again

來源

2017-09-22 14:01:15 BugraDayi

Laravel 5.4將json保存到數據庫

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