Django的API休息過濾多對多

Question

我是一個很新的Django和Django的阿比REST框架

我試圖發展與一個多對多關係

models.py

class Category(models.Model): 
    name = models.CharField(max_length=100) 

class Apartment(models.Model): 
    id_2 = models.IntegerField(default= None) 
    neighborhood = models.CharField(max_length=100) 
    name = models.CharField(max_length=120) 
    district = models.CharField(max_length=120) 
    created = models.DateTimeField() 
    cats = models.ManyToManyField(Category) 
    address = models.CharField(max_length=200) 
    postal_code = models.IntegerField() 
    latitude = models.FloatField() 
    longitude = models.FloatField() 

relationated兩種型號的API

serializers.py

class CategorySerializer(serializers.HyperlinkedModelSerializer): 
    class Meta: 
     model = Category 
     fields = ('id', 'name') 

class AptSerializer(serializers.HyperlinkedModelSerializer): 

    cats = CategorySerializer(many=True, read_only=True) 

    class Meta: 
     model = Apartment 
     fields = ('id_2', 'neighborhood', 'name','district','created','cats','address','postal_code','latitude','longitude') 

view.py

class AptViewSet(viewsets.ModelViewSet): 
    """ 
    API endpoint that allows groups to be viewed or edited. 
    """ 
    queryset = Apartment.objects.all() 
    serializer_class = AptSerializer 
    filter_backends = (filters.DjangoFilterBackend,) 
    filter_fields = ('id_2', 'neighborhood', 'name', 'district','created','cats','address','postal_code','latitude','longitude') 

routers.py

router.register(r'apartments', views.AptViewSet) 

正如你可以看到它實現DjangoFilterBackend所以現在我可以篩選網址鍵入

http://localhost:8000/apartments/?district=Eixample 

和我得到這個

{ 
    "id_2": 1044121532, 
    "neighborhood": "la Nova Esquerra de l'Eixample", 
    "name": "Hotel Exe AB Viladomat", 
    "district": "Eixample", 
    "created": "2001-02-13T00:00:00Z", 
    "cats": [ 
     { 
      "id": 1073, 
      "name": "Allotjament" 
     }, 
     { 
      "id": 1075, 
      "name": "Hotels" 
     }, 
     { 
      "id": 1076, 
      "name": "3 estrelles" 
     } 
    ], 
    "address": "Viladomat 197", 
    "postal_code": 8015, 
    "latitude": 41.383665702777776, 
    "longitude": 2.151834694444444 
}, 

我想要t o讓請求像

http://localhost:8000/apartments/?cats_name=Hotels 

但它不工作，任何想法，在哪裏將從現在的道路？ 編寫一個自定義過濾器？ 爲Category對象編寫另一個ViewSet？

謝謝

Answer 1

Manager提供的根QuerySet描述數據庫表中的所有對象。但是，通常情況下，您只需要選擇完整對象集的一部分。

但在這裏，您將可以通過查詢參數，並在整個查詢集

views.py

class AptViewSet(viewsets.ModelViewSet): 
    """ 
    API endpoint that allows groups to be viewed or edited. 
    """ 
    queryset = Apartment.objects.all() 
    serializer_class = AptSerializer 

    def get_queryset(self): 
     queryset = super(AptViewSet, self).get_queryset() 
     cats_name = self.request.query_params.get('cat_name', None) 
     if cats_name: 
      queryset = queryset.filter(cats__name=cats_name) 
     return queryset 

過濾如果你能遵循這個職位編寫自定義過濾器How to Pass kwarg to Filter

Answer 2

退房的查詢參數過濾this鏈接。

您將覆蓋序列化程序中的get_queryset方法。