如何字符串列表轉換爲INT

Question

的名單我在名單

a = [['1','2','3','4'],['1','2','3','4'],['1','2','3','4']] 

有這個名單，但我需要它是整數， 林不知道在哪裏可以使用int（）來改變海峽使用嵌套list comprehension爲int

a = [[1,2,3,4],[1,2,3,4],[1,2,3,4]] 

Answer 1

您可以使用嵌套列表comprehe nsion像這樣：

a = [['1','2','3','4'],['1','2','3','4'],['1','2','3','4']] 
b = [ [int(j) for j in i] for i in a] 

Answer 2

一個例子：

In [1]: a = [['1','2','3','4'],['1','2','3','4'],['1','2','3','4']] 

In [2]: [[int(s) for s in l] for l in a] 
Out[2]: [[1, 2, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4]] 

Answer 3

In [51]: a = [['1','2','3','4'],['1','2','3','4'],['1','2','3','4']] 

In [52]: [map(int, l) for l in a] 
Out[52]: [[1, 2, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4]] 

Answer 4

這裏有一個想法：

>>> a = [['1','2','3','4'],['1','2','3','4'],['1','2','3','4']] 
>>> map(lambda l: map(int, l), a) 
[[1, 2, 3, 4], [1, 2, 3, 4], [1, 2, 3, 4]]