Python Int對​​象不可調用

Question

請幫忙！我不明白這裏的錯誤。爲什麼當我輸入0,1或2以外的數字時，出現錯誤：「'int'object is not callable」？相反，假設打印出「您輸入的數字不正確，請重試」，然後回到提問。

第二個問題：我該如何更改代碼，即使我輸入字母字符，它也不會給我Value Error並繼續重新提問？謝謝！

def player_action():   
    player_action = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: ")) 

    if player_action == 0: 
     print ("Thank You, you chose to stay") 


    if player_action == 1: 
     print ("Thank You, you chose to go up") 

    if player_action == 2: 
     print ("Thank You, you chose to go down") 

    else: 
     print ("You have entered an incorrect number, please try again") 
     player_action() 

player_action() 

Answer 1

你應該改變變量名@Pedro洛比託建議，使用while環路@Craig建議，並且還可以包括try...except語句，但不的方式@ polarisfox64做到了，因爲他已經把它在錯誤的位置。

這裏是供您參考的完整版本：

def player_action():  
    while True: 
     try: 
      user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: ")) 
     except ValueError: 
      print('not a number') 
      continue 

     if user_input == 0: 
      print ("Thank You, you chose to stay")   

     if user_input == 1: 
      print ("Thank You, you chose to go up") 

     if user_input == 2: 
      print ("Thank You, you chose to go down") 

     else: 
      print ("You have entered an incorrect number, please try again") 
      continue 
     break 

player_action() 

Answer 2

只要改變變量名player_action到功能的差異名稱，即：

def player_action(): 
    user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: ")) 
    if user_input == 0: 
     print ("Thank You, you chose to stay") 
    elif user_input == 1: 
     print ("Thank You, you chose to go up") 
    elif user_input == 2: 
     print ("Thank You, you chose to go down") 
    else: 
     print ("You have entered an incorrect number, please try again") 
     player_action() 

player_action() 

Answer 3

首先回答你的問題已經被佩德羅回答，但作爲第二個答案，一嘗試不同的說法應該解決這個問題：

編輯：噢，抱歉，我搞砸了一點點......有更好的答案，但我想我應該花時間來解決這個問題

def player_action(): 
    try: 
     player_action_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: ")) 
    except ValueError: 
     print("Non valid value") # or somehting akin 
     player_action() 
    if player_action_input == 0: 
     print ("Thank You, you chose to stay") 
    elif player_action_input == 1: 
     print ("Thank You, you chose to go up") 
    elif player_action_input == 2: 
     print ("Thank You, you chose to go down") 
    else: 
     print ("You have entered an incorrect number, please try again") 
      player_action() 

player_action()