我有下面的代碼:遞歸調用函數返回的對象
// Core Zoom Logic, independent of event listeners.
$.zoom = function(target, source, img) {
var outerWidth,
outerHeight,
xRatio,
yRatio,
offset,
position = $(target).css('position');
// This part of code is omitted
return {
init: function() {
outerWidth = $(target).outerWidth();
outerHeight = $(target).outerHeight();
xRatio = (img.width - outerWidth)/$(source).outerWidth();
yRatio = (img.height - outerHeight)/$(source).outerHeight();
offset = $(source).offset();
},
move: function (e) {
var left = (e.pageX - offset.left),
top = (e.pageY - offset.top);
top = Math.max(Math.min(top, outerHeight), 0);
left = Math.max(Math.min(left, outerWidth), 0);
img.style.left = (left * -xRatio) + 'px';
img.style.top = (top * -yRatio) + 'px';
},
automove: function() {
// can I recall this?
}
};
};
我想實現的是加在汽車移動下面的效果()函數:
$(img).animate({
top: newTop,
left: newLeft,
}, 1000, function() {
automove(); /* recall */
});
但如何從它的身體再次調用automove?也許我應該徹底改變在$ .zoom函數中聲明函數的方式嗎?