f應該是一個類 - 你有一個功能。
見下文:
// Class acts like a function - also known as functor.
template<typename T, int a, int b>
class f
{
int operator()(T v)
{
return v*a-b; // just do something for example
}
};
template<typename T, int a, int b, template<typename,int,int> class func>
class C
{
int f()
{
return func<T,a,b>(3);
}
};
int main()
{
C<float,3,2, f> c;
}
...而改編版本,如果你需要移植遺留代碼(適應函數類模板):
#include <iostream>
template<typename T, int a, int b>
int f(T v)
{
std::cout << "Called" << std::endl;
return v*a-b; // just do something for example
}
template<typename T, int a, int b, template<typename,int,int> class func>
struct C
{
int f()
{
return func<T,a,b>(3);
}
};
template <class T, int a, int b>
struct FuncAdapt
{
T x_;
template <class U>
FuncAdapt(U x)
: x_(x)
{}
operator int() const
{
return f<T,a,b>(x_);
}
};
int main()
{
C<float,3,2, FuncAdapt > c;
c.f();
}
你究竟想達到什麼目的? – nijansen
我的編譯器在執行這段代碼時崩潰了。 – Saksham
@nijansen是不是MSVS2010穩定? – Saksham