0
我想在jqGrid的（4.3.2），顯示行沒有帶得到了成功呢。我的web服務的反應是：的jqGrid不顯示行
{"d":
{"__type":"JSONResponse:pe",
"ActionType":null,
"JSONData":"
{\"total\":1,
\"page\":1,
\"records\":5,
\"rows\":[
{\"invid\":1,\"cell\":[{\"invid\":1,\"amount\":500,\"tax\":65,\"total\":565,\"note\":\"myNote 0\"}]},
{\"invid\":2,\"cell\":[{\"invid\":2,\"amount\":510,\"tax\":75,\"total\":585,\"note\":\"myNote 1\"}]},
{\"invid\":3,\"cell\":[{\"invid\":3,\"amount\":520,\"tax\":85,\"total\":605,\"note\":\"myNote 2\"}]},
{\"invid\":4,\"cell\":[{\"invid\":4,\"amount\":530,\"tax\":95,\"total\":625,\"note\":\"myNote 3\"}]},
{\"invid\":5,\"cell\":[{\"invid\":5,\"amount\":540,\"tax\":105,\"total\":645,\"note\":\"myNote 4\"}]}
]
}",
"Status":false
}
} < - （假設在上面的代碼中這個大括號）
我的網格配置是這樣的： -
<script type="text/javascript">
$(document).ready(function() {
gridConfig();
});
function gridConfig() {
var request = JSON.stringify(requestData());
var jsonResponse;
$("#list").jqGrid({
url: '/ScriptServices/JsonService.svc/Process',
ajaxGridOptions: { contentType: 'application/json; charset=utf-8' },
datatype: 'json',
postData: { request: function() { return request; } },
mtype: 'GET',
colNames: ['Inv No', 'Amount', 'Tax', 'Total', 'Notes'],
colModel: [
{ name: 'invid', index: 'invid', width: 55 },
{ name: 'amount', index: 'amount', width: 80, align: 'right' },
{ name: 'tax', index: 'tax', width: 80, align: 'right' },
{ name: 'total', index: 'total', width: 80, align: 'right' },
{ name: 'note', index: 'note', width: 150, sortable: false }
],
pager: $('#pager'),
rowNum: 10,
rowList: [10, 20, 30],
sortname: 'invid',
sortorder: 'desc',
viewrecords: true,
jsonReader: {
root: "d.JSONData.rows",
page: "d.JSONData.page",
total: "d.JSONData.total",
records: "d.JSONData.records",
cell: "cell",
id:0
},
caption: 'My first grid'
});
};
function requestData() {
var request;
request = {
ActionType: 'GET_GRID_DATA',
RequestJSONData: '{ }'
};
return request;
}
</script>
我無法找到問題。是否需要其他格式。幫助請..
UPDATE1：
現在我的數據是奧列格建議經過適當JSON格式的到來，而是因爲在我的JSON數據__type額外領域，其無法正常渲染。
改性JSON數據看起來像： -
{
"d":
{"__type":"JSONResponse:pe",
"ActionType":"GRID_RESP",
"JSONData":
{"__type":"JQGridJSONReader:pe",
"total":1,
"page":1,
"records":5,
"rows":[
{"__type":"InvoiceGrid:pe",
"invid":1,
"cell":[{"__type":"JqGridCell:pe","invid":1,"amount":500,"tax":65,"total":565,"note":"myNote 0"}]},
.... and More Rows
]
},
"Status":true
}
} < - （假設在上面的代碼本的大括號）
我已經檢查這個link和實現的默認構造建議，protected internal是不可能在我的情況。
我的服務的配置是這樣的：
<system.serviceModel>
<services>
<service name="JsonService" behaviorConfiguration="JsonServiceAspNetAjaxBehavior">
<endpoint address="" behaviorConfiguration="JsonServiceEndPointBehavior"
binding="webHttpBinding" contract="JsonService" />
</service>
</services>
<behaviors>
<endpointBehaviors>
<behavior name="JsonServiceEndPointBehavior">
<enableWebScript/>
<dataContractSerializer ignoreExtensionDataObject="true" />
</behavior>
</endpointBehaviors>
<serviceBehaviors>
<behavior name="JsonServiceAspNetAjaxBehavior">
<serviceMetadata httpGetEnabled="true"/>
<serviceDebug includeExceptionDetailInFaults="true" />
</behavior>
</serviceBehaviors>
</behaviors>
<serviceHostingEnvironment aspNetCompatibilityEnabled="true"
multipleSiteBindingsEnabled="true" />
</system.serviceModel>
如果我申請到<webHttp/>我endpointBehaviors得到「變量UriTemplate查詢的值必須具有可以通過‘QueryStringConverter’轉換類型」的錯誤。
我的web服務是這樣的： -
[ServiceContract(Namespace = "http://www.abhishek.com/portal/json")]
[AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)]
public class JsonService
{
[OperationContract]
[WebInvoke(Method = "GET", RequestFormat = WebMessageFormat.Json,
ResponseFormat = WebMessageFormat.Json, BodyStyle = WebMessageBodyStyle.WrappedRequest)]
[GenerateScriptType(typeof(JsonService), ScriptTypeId = "JsonService1")]
public PresentationEntities.JSONResponse Process(PresentationEntities.JSONRequest request)
{
JSONResponse response;
try
{
if (request == null)
{
throw new ArgumentNullException("request", string.Format(ExceptionHelper.ARG_NULL_EXP_MSG, "JSONManager"));
}
else
{
JQGridTransalator gridtransalator = new JQGridTransalator();
response = gridtransalator.JQGridToJSONResponse(); // fill response.JSONData with JQGridJSONReader
}
}
catch (Exception)
{
throw;
}
return response;
}}
JQGridJSONReader是這樣的： -
[DataContract(Name = "JQGridJSONReader", Namespace = "pe")]
public class JQGridJSONReader
{
public JQGridJSONReader()
{
}
[DataMember(Name = "total", Order = 1)]
public int Total { get; set; }
[DataMember(Name = "page", Order = 2)]
public int Page { get; set; }
[DataMember(Name = "records", Order = 3)]
public int Records { get; set; }
[DataMember(Name = "rows", Order = 4)]
public List<InvoiceGrid> Rows { get; set; }
}
任何建議從JSON數據刪除__type。
UPDATE2：
更新的代碼，這樣我可以更清楚
[DataContract(Name = "InvoiceGrid", Namespace = "pe")]
public class InvoiceGrid
{
[DataMember(Name = "cell", Order = 2)]
public List<JqGridCell> Cell { get; set; }
}
[DataContract(Name = "JqGridCell", Namespace = "pe")]
public class JqGridCell
{
[DataMember(Name = "invid", Order = 1)]
public int Invid { get; set; }
[DataMember(Name = "invdate", Order = 2)]
public DateTime InvDate { get; set; }
[DataMember(Name = "amount", Order = 3)]
public double Amount { get; set; }
[DataMember(Name = "tax", Order = 4)]
public double Tax { get; set; }
[DataMember(Name = "total", Order = 5)]
public double Total { get; set; }
[DataMember(Name = "note", Order = 6)]
public string Note { get; set; }
}
我糾正了我的json數據，現在它的好來臨。但__type是額外的領域，我與json數據相互影響我的jsonReader格式。請參閱** Update1 ** – abhishekrvce
我收到了錯誤消息。誤差在' 「小區」：[{ 「__類型」： 「JqGridCell：PE」， 「因維」：1， 「量」：500， 「稅」：65， 「總」：565， 「注意」：「myNote 0" }]}，'。很快我會發布答案。感謝@ Oleg給我提示如何將.net對象轉換爲json對象。 – abhishekrvce
是的，我手動使用JSON序列化。糾正了這一點。可能在將來發送響應時，我永遠不會那樣做，因爲ASP.NET已經把它給我。 :) – abhishekrvce