我想在ajax後獲得響應,但總是返回NULL。
我在想,已經嘗試了所有我可以......但希望有人能夠解決它。首先十分感謝。如果需要更多信息,請告訴我。
注:PHP function not returning any data to JQuery ajax method - 這個環節並沒有幫助我
這裏是jQuery代碼:
var post_id=3;
$.ajax({
type: "POST",
url: "profile/ajax_get_new_posts",
data: { post_id : post_id },
dataType: 'json',
success: function(data){
console.log(data);
var current_content = $("ol#posts_container").html();
$("ol#posts_container").html(data.content + current_content);
}
});
資料/ ajax_get_new_posts(它名爲.php)
function ajax_get_new_posts(){
header('Content-Type: application/json');
$post_id=$this->input->post('post_id');
$chat_messages_html='testing';
$result = array('status' => 'ok', 'content' => $chat_messages_html);
$result=json_encode($result);
return ($result);
exit();
}
如果我試着用var_dump($ result); die();給我正確的結果:
string(38) "{"status":"ok","content":"samoletite"}"
在響應頭給我的Content-Length:0(它正在測試在本地主機上......不www.mywebsite)
Remote Address:[::1]:80
Request URL:http://www.mywebsite/bg/profile/ajax_get_new_posts
Request Method:POST
Status Code:200 OK
Request Headersview source
Accept:application/json, text/javascript, */*; q=0.01
Accept-Encoding:gzip,deflate
Accept-Language:en-US,en;q=0.8
Connection:keep-alive
Content-Length:9
Content-Type:application/x-www-form-urlencoded
Host:localhost
Origin:http://localhost
Referer:http://www.mywebsite/bg/profile
User-Agent:Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.111 Safari/537.36
X-Requested-With:XMLHttpRequest
Form Dataview sourceview URL encoded
post_id:3
Response Headersview source
Connection:Keep-Alive
Content-Length:0
Content-Type:application/json
Date:Fri, 31 Oct 2014 13:24:56 GMT
Keep-Alive:timeout=5, max=97
.......
CONSOLE.LOG給我:
null --->ajaxPostProfile.js:28
Uncaught TypeError: Cannot read property 'content' of null --->ajaxPostProfile.js:31
謝謝你非常非常....謝謝你救了我的時間從10個小時尋找解決方案。乾杯! – 2014-10-31 13:48:26
不客氣!請將此答案設爲正確。謝謝。 – 2014-10-31 14:09:33