我想讓最後一次只捐獻血的用戶6個月向我發送請求。我嘗試過所有可能的人性化功能,並且耗盡了全面的Google搜索功能。請幫忙。我想檢查一下我的mysql數據庫,看看用戶在過去六個月裏是否捐了血,如果他沒有我想讓他捐出
<?php
session_start();
$con=mysqli_connect(*);
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if(isset($_POST['Request']))
{
$result=mysqli_query($con,"SELECT `req_date`,`Mobile` FROM `pend` WHERE `Mobile` LIKE '" . mysql_escape_string($_POST['Mobile']) ."' AND `req_date` <= (now() - INTERVAL 6 MONTH); ");
$count=mysqli_num_rows($result);
if (!$result)
{
printf("Error: %s\n", mysqli_error($con));
exit();
}
echo (mysqli_info($con));
if ($count>0)
{
$query=mysqli_query($con,"INSERT INTO pend(Name,Mobile,Station,Bld_grp,Email) SELECT Name,Mobile,Station,Bld_grp,Email FROM regi WHERE Mobile LIKE '" . mysql_escape_string($_POST['Mobile']) . "'; ");
if (!$query)
{
printf("Error: %s\n", mysqli_error($con));
exit();
}
$row =mysqli_fetch_array($query,MYSQLI_BOTH);
$Mmobile = $row['Mobile'];
if($Mobile == $Mmobile) {
header('Location:http://www.mbdr.ml/test/rec.html');
} else {
echo "You don't belong in our database register first";
}
}
}
else
{
header(' Location:http://www.mbdr.ml/test/servic.html ');
}
?>
表格代號:在您的形式
<form action="mbdr.ml/test/rn.php"; method="post" name="frm1">
Kindly Enter Your Mobile Number Here!<br>
<input type="text" name="Mobile" placeholder="XXXXXXXXXX" align="center"> <br>
<input type="Submit" name="Request" value="Request">
<input type="Reset" name="Reset" value="Reset">
</form>
什麼是錯誤? –
@GoudaElalfy先生沒有顯示錯誤,它只是停留在持有腳本的頁面上,並且不會向前移動。 –
那麼請求是什麼?在你的代碼if(isset($ _ POST ['Request']))? –