Android：例外：連接超時

我一直得到這個問題例外：連接超時我在另一臺設備上運行我的項目，所以我必須使用IP地址。所以我改變localhost:8080/lab/lab1.xml爲http://192.168.1.5/lab/lab1.xml 現在我運行後，它加載一段時間後加載它的設備上，然後顯示空白頁。當我檢查Logcat它顯示異常：連接超時請幫助我。由於Android：例外：連接超時

因此，這裏是MainActivity.java

import android.app.Activity; 
import android.app.ProgressDialog; 
import android.os.AsyncTask; 
import android.os.Bundle; 
import android.widget.TextView; 

public class MainActivity extends Activity { 

    TextView tvResponse; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     tvResponse = (TextView) findViewById(R.id.tvResponse); 
     new PostAsync().execute(); 
    } 

    class PostAsync extends AsyncTask<Void, Void, Void> { 
     ProgressDialog pd; 
     XMLHelper helper; 


     @Override 
     protected void onPreExecute() { 
      pd = ProgressDialog.show(MainActivity.this, "by Es", "Loading", true, false); 
     } 
     @Override 
     protected Void doInBackground(Void... arg0) { 
      helper = new XMLHelper(); 
      helper.get(); 
      return null; 
     } 


     @Override 
     protected void onPostExecute(Void result) { 
      StringBuilder builder = new StringBuilder(); 
      for(EventValue event : helper.events) { 
       builder.append("\nWhat: " + event.getWhat()); 
       builder.append("\nWhen: " + event.getWhen()); 
       builder.append("\nWhere: " + event.getWhere()); 
       builder.append("\n"); 
      } 
      tvResponse.setText(builder.toString()); 
      pd.dismiss(); 
     } 

    } 

}

這裏是XMLHelper.java

import java.io.InputStream; 
import java.net.URL; 
import java.util.ArrayList; 

import javax.xml.parsers.SAXParser; 
import javax.xml.parsers.SAXParserFactory; 

import org.xml.sax.Attributes; 
import org.xml.sax.InputSource; 
import org.xml.sax.SAXException; 
import org.xml.sax.XMLReader; 
import org.xml.sax.helpers.DefaultHandler; 

import android.util.Log; 

public class XMLHelper extends DefaultHandler { 
    /** 
    * The URL to be parsed 
    */ 
    private String URL_MAIN = "http://192.168.1.5/lab/lab1.xml"; 
    String TAG = "XMLHelper"; 

    Boolean currTag = false; 
    String currTagVal = ""; 
    public EventValue event = null; 
    public ArrayList<EventValue> events = new ArrayList<EventValue>(); 


    public void get() { 
     try { 
      SAXParserFactory factory = SAXParserFactory.newInstance(); 
      SAXParser mSaxParser = factory.newSAXParser(); 
      XMLReader mXmlReader = mSaxParser.getXMLReader(); 
      mXmlReader.setContentHandler(this); 
      InputStream mInputStream = new URL(URL_MAIN).openStream(); 
      mXmlReader.parse(new InputSource(mInputStream)); 
     } catch(Exception e) { 
      // Exceptions can be handled for different types 
      // But, this is about XML Parsing not about Exception Handling 
      Log.e(TAG, "Exception: " + e.getMessage()); 
     } 
    } 


    @Override 
    public void characters(char[] ch, int start, int length) 
      throws SAXException { 
     if(currTag) { 
      currTagVal = currTagVal + new String(ch, start, length); 
      currTag = false; 
     } 
    } 


    @Override 
    public void endElement(String uri, String localName, String qName) 
      throws SAXException { 
     currTag = false; 

     if(localName.equalsIgnoreCase("what")) 
      event.setWhat(currTagVal); 

     else if(localName.equalsIgnoreCase("when")) 
      event.setWhen(currTagVal); 

     else if(localName.equalsIgnoreCase("where")) 
      event.setWhere(currTagVal); 

     else if(localName.equalsIgnoreCase("event")) 
      events.add(event); 
    } 


    @Override 
    public void startElement(String uri, String localName, String qName, 
      Attributes attributes) throws SAXException { 
     Log.i(TAG, "TAG: " + localName); 

     currTag = true; 
     currTagVal = ""; 

     if(localName.equals("event")) 
      event = new EventValue(); 
    } 
}

這裏是EventValue.java

public class EventValue { 
    String what, when, where; 

    public String getWhat() { 
     return what; 
    } 

    public void setWhat(String what) { 
     this.what = what; 
    } 

    public String getWhen() { 
     return when; 
    } 

    public void setWhen(String when) { 
     this.when = when; 
    } 

    public String getWhere() { 
     return where; 
    } 

    public void setWhere(String where) { 
     this.where = where; 
    } 



}

這裏是XML文件lab1.xml（localhost：8080/lab/lab1.xml）

<event> 
    <what>Summer</what> 
    <when>March1</when> 
    <where>--</where> 
</event> 

<event> 
    <what>asdasdas</what> 
    <when>March 2</when> 
    <where>asasas</where> 
</event> 

<event> 
    <what>asdasdq</what> 
    <when>asdasdx</when> 
    <where>asdasdf</where> 
</event>

來源

2014-04-01 dotamon

我假設你在清單中設置了互聯網權限，看起來你錯過了其他平板電腦ip地址的端口號。 – chaitanya

你可以在應用程序之外自己訪問xml文件嗎？目錄中是否有密碼，以便在您獲得訪問權限之前提示您？ – Gyhth

@chaitanya你是什麼意思錯過了其他平板電腦的IP地址端口號？ – dotamon

如果您正在使用8080端口，那麼你應該使用在連接URL：

http://192.168.1.5:8080/lab/lab1.xml

這也將是一個好主意，檢查是否可以訪問來自另一臺機器的瀏覽器的網址。

來源

2014-04-01 18:26:36 gtsouk

Thankyou這麼多 – dotamon

不客氣。不要忘記接受答案。 – gtsouk

Android：例外：連接超時

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