2010-09-22 49 views
1

對於AS3來說,讀取和存儲數據的方式是最快的。對於現在的調試,它只是讀取原始XML,但我懷疑如果我將它們變成嵌套數組,它會更快。在AS3中存儲和解析數據的最有效方式是什麼?

將XML解析爲嵌套數組以供稍後閱讀是最有效的方法?還是有更好的方法來讀取大量數據?

+1

定義「大量數據」。 – Raveline 2010-09-22 08:56:18

回答

1

好pasring一個xml到數組具有各種優勢,如上面提到的意見.. 您將如何得到嵌套數組的示例XML

<mynode4 swf="node4.swf" htmlpage=""> 
<subheading1 swf="L4_s1.swf"  htmlpage="L4_1.htm">Work Hard</subheading1> 
<subheading2 swf="L4_s2.swf"  htmlpage="L4_2.htm">karachi</subheading2> 
<subheading3 swf="L4_s3.swf"  htmlpage="L4_3.htm">Newyork City.</subheading3> 
</mynode4>  
<mynode5 swf="five.swf" htmlpage="">Here is the Test for node 5</mynode5> 
<mynode6 swf="six.swf" htmlpage="">Last node accessed</mynode6> 

VAR uLoader:的URLLoader = new URLLoader() uLoader.addEventListener(Event.COMPLETE,onXMLLoaded) uLoader.load(new URLRequest(「xmldata.xml」))

公共函數onXMLLoaded(事件:事件):無效{

var loader:URLLoader = URLLoader(event.target); 
    var root1:XML = new XML(loader.data); 
    var showChilds:XMLList = root1.children(); 
    var nodes_names2   :Array = new Array(); 
    var nodes_swf2    :Array = new Array(); 
    var nodes_values2   :Array = new Array(); 
    var nodes_pages2   :Array = new Array(); 


    var take_items:Array = recursiveXML(showChilds,nodes_names2,nodes_swf2,nodes_values2,nodes_pages2,0); 
    this.nodes_names2  = take_items[0]; 
    this.nodes_swf2   = take_items[1]; 
    this.nodes_values2  = take_items[2]; 
    this.nodes_pages2  = take_items[3]; 

    trace(nodes_names2); 
    trace(nodes_swf2); 
    trace(nodes_values2); 
    trace(nodes_pages2); 

}

公共函數recursiveXML(showChilds:XMLList中,nodes_names:陣列,nodes_swf:陣列,nodes_values:陣列,nodes_pages:陣列, count:int):Array {

 for each (var eachChild:XML in showChilds) 
     { 
      if(eachChild.hasComplexContent()) 
      { 
       nodes_names[count]   = new Array((eachChild.children().length())) 
       nodes_swf[count]   = new Array((eachChild.children().length())) 
       nodes_values[count]   = new Array((eachChild.children().length())) 
       nodes_pages[count]   = new Array((eachChild.children().length())) 

       nodes_names[count][0]  = eachChild.name() 
       nodes_swf[count][0]   = eachChild.attribute("swf"); 
       nodes_values[count][0]  = ""; 
       nodes_pages[count][0]  = ""; 
       var showChilds:XMLList  = eachChild.children(); 
       var take_items:Array  = recursiveXML(showChilds,nodes_names[count],nodes_swf[count],nodes_values[count],nodes_pages[count] , 1); 
       nodes_names[count]   = take_items[0]; 
       nodes_swf[count]   = take_items[1]; 
       nodes_values[count]   = take_items[2]; 
       nodes_pages[count]   = take_items[3]; 
       count++; 
      } 
      else 
      { 
       nodes_names[count]   = eachChild.name(); 
       nodes_swf[count]   = eachChild.attribute("swf"); 
       nodes_pages[count]   = eachChild.attribute("htmlpage");  
       nodes_values[count]   = eachChild.text(); 
       count++; 
      } 
     } 
      var _items:Array = new Array(nodes_names, nodes_swf,nodes_values,nodes_pages); 
      return _items; 
    } 
0

第一次解析XML時,您可以將數據存儲在Object中,以便隨後在需要時更容易/更快地檢索一組屬性。

如果您願意,可以將此對象視爲多維數組。

1

與Array.sortOn方法結合使用時,轉換爲對象也可能會有所幫助。您也可以考慮使用JSON作爲傳輸格式;它將消除解析和轉換XML的開銷。

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