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所以我的問題是,我掛在第二個聲明。我應該允許用戶放置多行輸入(全部同時輸入),while循環在所有輸入使用後自行結束,輸入如下一次輸入多行輸入
速度限制爲40英里,但是你要超過65
99瓶......
的代碼只使用第一個輸入然後關閉,當我使用scan.hasNextLine它停留在一個無限循環
public static void main(String[] args) throws IOException {
Scanner scan = new Scanner(System.in);
Scanner scan2 = new Scanner(System.in);
List<Integer> numbers = new ArrayList<>();
Pattern p = Pattern.compile("([-+]?[0-9]+(?:\\.[0-9]+)?)");
String phrase;
String[] tens = { "Ten", "Twenty", "Thirty", "Fourty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
String[] teens = { "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen",
"Nineteen" };
String[] ones = { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
phrase = scan.nextLine();
Matcher m = p.matcher(phrase);
while (m.find()) {
numbers.add(Integer.parseInt(m.group()));
}
// Solve
while (There is another line of input) {// i need some help here!!!
for (int i = 0; i < numbers.size(); i++) {
if (numbers.get(i) >= 20) {
if (numbers.get(i) % 10 == 0) {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)),
tens[((numbers.get(i) - numbers.get(i) % 10)/10) - 1]);
} else {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)),
(tens[((numbers.get(i) - numbers.get(i) % 10)/10) - 1] + "-"
+ ones[numbers.get(i) % 10]));
}
} else if (numbers.get(i) < 20 && numbers.get(i) > 10) {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)), teens[(numbers.get(i) % 10) - 1]);
} else if (numbers.get(i) < 10 && numbers.get(i) > 0) {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)), ones[numbers.get(i)]);
} else if (numbers.get(i) == 10) {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)), "Ten");
} else if (numbers.get(i) == 0) {
phrase = phrase.replaceAll(Integer.toString(numbers.get(i)), "Zero");
}
}
}
System.out.println(phrase);
}
你說「我應該允許用戶把有輸入(在同一時間全部定)的多行」。所以,多行文本被粘貼到控制檯上,然後按下Enter鍵,對吧?你有沒有嘗試在'hasNextLine()'之後再做一個'scan.nextLine()'? –
忽略我以前的ramblings,這是考慮:http://stackoverflow.com/a/23713487/5629413 –
如果我的答案幫助你,你可以接受它作爲答案。 –