如何在liferay portlet中使用ajax返回對象？

我需要在成功方法上返回一個字符串。這是我在jsp頁面中的AJAX代碼。如何在liferay portlet中使用ajax返回對象？

<portlet:actionURL name="filterDocuments" var="filterDocuments"> 
    <portlet:param name="action" value="filterDocuments"/> 
</portlet:actionURL> 

<script type="application/javascript"> 
    var filterDto = { 
     page: 0, 
     tags: {}, 
     search: null 
    }; 
    $.ajax({ 
     type: "POST", 
     url: "<%=filterDocuments%>", 
     data: filterDto, 
     success: function (msg) { 
      alert(msg); 
     } 
    }); 
</script>

這裏是我在後端的處理程序。

@ActionMapping(params = "action=filterDocuments") 
    public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException { 
     PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter(); 
     writer.write("text"); 
     writer.flush(); 
     writer.close(); 
    }

結果它顯示了警告消息中的空字符串。如何處理它？

UPDATE 我改變控制器方法

@ResourceMapping(value = "filterDocuments") 
public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException { 
    PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter(); 
    writer.write("text"); 
    writer.flush(); 
    writer.close(); 
}

和URL在我的JSP是

<portlet:resourceURL var="ajaxResourceURL"/> 

<script type="application/javascript"> 
    var filterDto = { 
     page: 0, 
     tags: {}, 
     search: null 
    }; 
    $.ajax({ 
     type: "POST", 
     url: "<%=ajaxResourceURL%>", 
     data: filterDto, 
     success: function (msg) { 
      alert(msg); 
     } 
    }); 
</script>

而現在它給了我一個異常

org.springframework。 web.portlet.NoHandlerFoundException：找不到處理程序門戶請求：模式 '觀看'，相位 'RESOURCE_PHASE'，參數映射[ '搜索' - >陣列[ '']， '頁' - >陣列[ '0']]

全控制器類

@Controller 
@RequestMapping("VIEW") 
@Log4j 
public class SpringMVCController extends MVCPortlet { 




    @RenderMapping 
    public String view(RenderRequest request, RenderResponse response) { 


     String view = PropertiesConfig.getAsString("views", request); 

     return view; 
    } 


    @Override 
    public void serveResource(ResourceRequest resourceRequest, 
           ResourceResponse resourceResponse) 
      throws IOException, PortletException { 
     try { 
      PrintWriter writer = resourceResponse.getWriter(); 
      writer.write("text"); 
      writer.flush(); 
      writer.close(); 
      CaptchaUtil.serveImage(resourceRequest, resourceResponse); 
     } catch (Exception e) { 
      log.error(e.getMessage()); 
     } 
    } 


    @ResourceMapping(value = "action=filterDocuments") 
    public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException { 
     PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter(); 
     writer.write("text"); 
     writer.flush(); 
     writer.close(); 
    } 


}

來源

2017-08-11 Serg Shapoval

與您的代碼的問題是，你調用'使用AJAX，這不是一個有效的模式actionURL'。 –

將'portlet：actionURL'改爲'portlet：resourceURL'和'@ ActionMapping'改爲'@ResourceMapping'。 –

[在portlet中使用json對象響應http請求]的可能重複（https://stackoverflow.com/questions/17592144/respond-to-http-request-with-json-object-in-portlet） –

與更新的代碼/是問題（一個或多個）以下：

我。您尚未根據您的portlet:actionURL指定portlet:resourceURL上的id屬性（具有所需的值）。將其更改爲：

<portlet:resourceURL id="filterDocuments" var="filterDocuments" />

ii。映射方法在行動類簽名不一樣的UI的portlet:resourceURL id屬性的值，將其更改爲：

@ResourceMapping("filterDocuments") 
public void filterDocuments(ResourceRequest request, ResourceResponse response) 
throws IOException, SystemException { 
    PrintWriter writer = response.getWriter(); 
    writer.write("text"); 
    writer.flush(); 
    writer.close(); 
}

III。從操作類中刪除另一個serveResource方法，因爲這僅適用於通用（默認）Portlet類型。

參考： Liferay Spring Portlet Tutorial

來源

2017-08-11 12:56:43

thanx。它有幫助。這liferay讓我發瘋 –

@SergShapoval，不客氣，快樂編碼！ –

如何在liferay portlet中使用ajax返回對象？

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