0
我正在嘗試使用tomcat認證爲我的spring web服務配置預認證。我嘗試了pre-auth spring示例並像下面那樣配置了我的applicationContext-security.xml以使用默認彈簧配置。Spring Web服務預認證過濾器映射角色
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:sec="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd">
<bean id="filterChainProxy" class="org.springframework.security.web.FilterChainProxy">
<sec:filter-chain-map path-type="ant">
<sec:filter-chain pattern="/**" filters="sif,j2eePreAuthFilter,logoutFilter,etf,fsi"/>
</sec:filter-chain-map>
</bean>
<bean id="sif" class="org.springframework.security.web.context.SecurityContextPersistenceFilter"/>
<sec:authentication-manager alias="authenticationManager">
<sec:authentication-provider ref='preAuthenticatedAuthenticationProvider'/>
</sec:authentication-manager>
<bean id="preAuthenticatedAuthenticationProvider" class="org.springframework.security.web.authentication.preauth.PreAuthenticatedAuthenticationProvider">
<property name="preAuthenticatedUserDetailsService" ref="preAuthenticatedUserDetailsService"/>
</bean>
<bean id="preAuthenticatedUserDetailsService"
class="org.springframework.security.web.authentication.preauth.PreAuthenticatedGrantedAuthoritiesUserDetailsService"/>
<bean id="j2eePreAuthFilter" class="org.springframework.security.web.authentication.preauth.j2ee.J2eePreAuthenticatedProcessingFilter">
<property name="authenticationManager" ref="authenticationManager"/>
<property name="authenticationDetailsSource">
<bean class="org.springframework.security.web.authentication.preauth.j2ee.J2eeBasedPreAuthenticatedWebAuthenticationDetailsSource">
<property name="mappableRolesRetriever">
<bean class="org.springframework.security.web.authentication.preauth.j2ee.WebXmlMappableAttributesRetriever" />
</property>
<property name="userRoles2GrantedAuthoritiesMapper">
<bean class="org.springframework.security.core.authority.mapping.SimpleAttributes2GrantedAuthoritiesMapper">
<property name="convertAttributeToUpperCase" value="true"/>
</bean>
</property>
</bean>
</property>
</bean>
<bean id="preAuthenticatedProcessingFilterEntryPoint"
class="org.springframework.security.web.authentication.Http403ForbiddenEntryPoint"/>
<bean id="logoutFilter" class="org.springframework.security.web.authentication.logout.LogoutFilter">
<constructor-arg value="/"/>
<constructor-arg>
<list>
<bean class="org.springframework.security.web.authentication.logout.SecurityContextLogoutHandler"/>
</list>
</constructor-arg>
</bean>
<bean id="servletContext" class="org.springframework.web.context.support.ServletContextFactoryBean"/>
<bean id="etf" class="org.springframework.security.web.access.ExceptionTranslationFilter">
<property name="authenticationEntryPoint" ref="preAuthenticatedProcessingFilterEntryPoint"/>
</bean>
<bean id="httpRequestAccessDecisionManager" class="org.springframework.security.access.vote.AffirmativeBased">
<property name="allowIfAllAbstainDecisions" value="false"/>
<property name="decisionVoters">
<list>
<ref bean="roleVoter"/>
</list>
</property>
</bean>
<bean id="fsi" class="org.springframework.security.web.access.intercept.FilterSecurityInterceptor">
<property name="authenticationManager" ref="authenticationManager"/>
<property name="accessDecisionManager" ref="httpRequestAccessDecisionManager"/>
<property name="securityMetadataSource">
<sec:filter-invocation-definition-source>
<sec:intercept-url pattern="/**" access="TESTROLE"/>
</sec:filter-invocation-definition-source>
</property>
</bean>
<bean id="roleVoter" class="org.springframework.security.access.vote.RoleVoter"/>
<bean id="securityContextHolderAwareRequestFilter" class="org.springframework.security.web.servletapi.SecurityContextHolderAwareRequestFilter"/>
這裏TESTROLE是在Tomcat中-users.xml中 定義的角色，但現在我得到下面的錯誤。
java.lang.IllegalArgumentException: Unsupported configuration attributes: [TESTROLE]
org.springframework.security.access.intercept.AbstractSecurityInterceptor.afterPropertiesSet(AbstractSecurityInterceptor.java:156)
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1541)
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1479)
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:521)
org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:458)
org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:295)
org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:223)
org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:292)
org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194)
org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:323)
org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:107)
org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveManagedList(BeanDefinitionValueResolver.java:353)
org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:154)
org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveManagedMap(BeanDefinitionValueResolver.java:379)
任何我想法，爲什麼發生這種情況？