在MySQL聲明+回行與大多數比賽

我有以下SQL查詢 - 注意：在口頭上更改不同的查詢：在MySQL聲明+回行與大多數比賽

SELECT a.pid,a.city,a.countryCode,b.zipEnabled,b.english 
FROM geoWorld AS a 
JOIN geoCountry AS b ON a.countryCode=b.countryCode 
WHERE a.city IN ("free","dating","donvale","australia");

我得到3點返回。

2場比賽'澳大利亞'和1場'donvale'和'澳大利亞'。

有沒有辦法讓我回到最高的比賽？

我可以用PHP來處理結果，但如果我可以單獨使用SQL來處理結果會很好。

歡呼

來源

2015-09-20 Adam

'集團通過a.city訂購數（a.city）desc'應該解決這個問題。 –

嗯，這是什麼意思？

SELECT w.countryCode, count(*) 
FROM geoWorld w JOIN 
    geoCountry c 
    ON w.countryCode = c.countryCode 
WHERE w.city IN ('free', 'dating', 'donvale', 'australia') 
GROUP BY w.countryCode 
ORDER BY count(*) DESC;

來源

2015-09-20 02:43:08

否...需要返回匹配IN語句中的2個值的行。有3個回報，只有一個匹配2個值...我想返回最匹配的行。 – Adam

@Adam。。。單行不能匹配兩個單獨的值。 –

@戈登林諾夫：我認爲最高記錄（第一）是按照亞當的預期結果。 – seahawk

使用「分組依據」：

select a.pid,a.city,a.countryCode, b.zipEnabled,b.english, a.c from ( 
    SELECT a.pid,a.city,a.countryCode, count(*) c 
    FROM geoWorld AS a 
    JOIN geoCountry AS b ON a.countryCode=b.countryCode 
    WHERE a.city IN ("free","dating","donvale","australia") 
    group by a.pid,a.city,a.countryCode 
) AS a JOIN geoCountry AS b ON a.countryCode=b.countryCode 
order by c desc

或

SELECT a.pid,a.city,a.countryCode,b.zipEnabled,b.english, 
    (select count(*) from geoCountry c where c.countryCode = a.countryCode) ct 
FROM geoWorld AS a 
JOIN geoCountry AS b ON a.countryCode=b.countryCode 
WHERE 
    a.city IN ("free","dating","donvale","australia") 
order by ct desc

，或者如果你「需要返回，在報表匹配2個值的行」具有使用的語句，例如：

select a.pid,a.city,a.countryCode, b.zipEnabled,b.english, a.c from ( 
    SELECT a.pid,a.city,a.countryCode, count(*) c 
    FROM geoWorld AS a 
    JOIN geoCountry AS b ON a.countryCode=b.countryCode 
    WHERE a.city IN ("free","dating","donvale","australia") 
    group by a.pid,a.city,a.countryCode 
    having c=2 
) AS a JOIN geoCountry AS b ON a.countryCode=b.countryCode 
order by c desc

來源

2015-09-20 02:49:31 wildloop

使用limit得到上面記錄着：

SELECT a.pid,a.city,a.countryCode,b.zipEnabled,b.english 
FROM geoWorld AS a 
JOIN geoCountry AS b ON a.countryCode=b.countryCode 
WHERE a.city IN ("free","dating","donvale","australia") 

Group by a.city Order by count(a.city) desc 
limit 1 ;

來源

2015-09-20 05:05:35 seahawk

在MySQL聲明+回行與大多數比賽

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