現在這一個似乎有點複雜,也許我已經讓自己超過我可以管理,但它似乎是我能達到我需要的唯一途徑。打印JSON(從一個PHP)通過AJAX到引導模式
我是一個完整的新手,我正在爲這個項目工作(這是整個項目中最複雜的事情),所以任何幫助將非常感謝!
我基本上有一個引導網頁,這個網頁顯示一個用戶列表(從一個while循環php)。我需要用戶能夠做的是從中選擇一個用戶,並以引導模式的形式編輯詳細信息。
到目前爲止,我有一切工作,模態加載等,並從各種來源網上爭吵JSon,但我從來沒有學到它,並且我的方式走出我的深淵。目前它正在每個字段中打印'[object HTMLCollection]'。
首先這裏是模態&列表中的HTML:
模態(這完全出現)
<div class="modal fade" id="editUserModal" tabindex="-1" role="dialog" aria-labelledby="editModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h2 class="modal-title" id="editModalLabel"></h2>
</div>
<div class="modal-body">
<form>
<div class="form-group">
<label for="username" class="control-label">Username:</label>
<input type="text" name="username" class="form-control" id="username"></input>
</div>
<div class="row">
<div class="col-lg-12">
<div class="form-group">
<label for="password" class="control-label">Password:</label>
<div class="input-group">
<span class="input-group-btn">
<input type="button" class="form-control" value="Change Password" onClick="changeRandomPassword();">
</span>
<input type="text" name="password" class="form-control" id="password" value="" required></input>
</div>
</div>
</div>
</div>
<div class="form-group">
<label for="firstName" class="control-label">First Name:</label>
<input type="text" name="firstName" class="form-control" id="firstName">
</div>
<div class="form-group">
<label for="lastName" class="control-label">Surname:</label>
<input type="text" name="lastName" class="form-control" id="lastName">
</div>
<div class="form-group">
<label for="jobTitle" class="control-label">Job Title:</label>
<input type="text" name="jobTitle" class="form-control" id="jobTitle">
</div>
<div class="form-group">
<label for="TaskTeam" class="control-label">Task Team:</label>
<input type="text" name="TaskTeam" class="form-control" id="TaskTeam">
</div>
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-danger" data-dismiss="modal">Cancel</button>
<button type="button" class="btn btn-success">Submit Changes</button>
</div>
</div>
</div>
</div>
這裏是PHP的列表:(在這裏再次沒有麻煩)
<?php
include("dbconnect.php");
$dbQuery= mysql_query("SELECT * FROM users ORDER BY lastName ASC;");
while($dbRow = mysql_fetch_array($dbQuery))
{
$userID = $dbRow['id'];
$username = $dbRow['username'];
$firstName = $dbRow['firstName'];
$lastName = $dbRow['lastName'];
$jobTitle = $dbRow['jobTitle'];
$userteam = $dbRow['TaskTeam'];
$admin = $dbRow['admin'];
echo '<tr>';
echo '<td>';
echo '<button type="button" class="btn btn-primary close" data-toggle="modal" data-target="#editUserModal" value='.$userID.' id="user" name="user"" data-user='.$userID.'><span title="Edit" aria-hidden="true" class="glyphicon glyphicon-edit"></span></button>';
echo '</td>';
echo '<td>'.$firstName.'</td>';
echo '<td>'.$lastName.'</td>';
echo '<td>'.$jobTitle.'</td>';
echo '<td>'.$userteam.'</td>';
echo '<td>'.$admin.'</td>';
echo '<td>';
echo '<a href="deleteUser.php?id='.$userID.'">';
echo '<button type="button" name="delete_row" id="delete_row" class="close">';
echo '<span title="Delete" aria-hidden="true" class="glyphicon glyphicon-trash">';
echo '</span>';
echo '<span class="sr-only">';
echo 'Delete';
echo '</span>';
echo '</button>';
echo '</a>';
echo '</td>';
echo '</tr>';
}
echo mysql_error();
mysql_close();
?>
這裏是問題所在:
<script>
$('#editUserModal').on('show.bs.modal', function (event)
{
var button = $(event.relatedTarget)
var recipient = button.data('user')
var modal = $(this)
modal.find('.modal-title').text('Edit ' + recipient + "'s details.")
$(function()
{
$.ajax(
{
type: 'GET',
url: "getUser.php?id=",
data: 'recipient',
dataType: "json",
success: function(data)
{
var obj = JSON.parse(data);
$.each(obj, function(key, val)
{
console.log(val);
var id = data[0];
var firstName = data[1];
var lastName = data[2];
var username = data[3];
var password = data[4];
var jobTitle = data[5];
var TaskTeam = data[6];
var admin = data[12];
});
}
})
})
modal.find('.modal-body #firstName').val(firstName)
modal.find('.modal-body #lastName').val(lastName)
modal.find('.modal-body #username').val(username)
modal.find('.modal-body #password').val(password)
modal.find('.modal-body #jobTitle').val(jobTitle)
modal.find('.modal-body #TaskTeam').val(TaskTeam)
})
</script>
最後這裏是php文件,以獲得用戶的詳細信息:(此作品太多,但僅完成manually-這是大宗它不包括口令等)
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$userid = intval($_GET['id']);
$sql="SELECT * FROM users WHERE id = $userid";
$result = $conn->query($sql);
/*
$user = array();
while ($row = mysql_fetch_array($result)) {
$details = array(
"username" => $row['username'],
"firstName" => $row['firstName'],
"lastName" => $row['lastName'],
"taskTeam" => $row['taskTeam']
);
$user[] = $details;
}
echo json_encode($user);
$conn->close();
*/
if ($result->num_rows > 0) {
// output data of each row
$array = array();
while($row = $result->fetch_assoc()) {
array_push($array, $row);
}
echo json_encode($array);
} else {
echo "0 results";
}
$conn->close();
對不起,缺乏的mysqli的,我知道這是最新的標準,目前正在實施這個項目。
任何幫助將是偉大的!由於
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