Laravel，該代碼的替代方式，而不改變其含義

Question

出現漂亮有什麼替代方法這是更短的和美麗？目前使用Maatwebsite/Laravel-Excel的

foreach ($rows as $key => $value) 
{ 
    if($value->{'red'} == 1) 
    { 
     DB::table('furnitures')->insert(
     [ 
      'chair' => $value->{'Chair Name'}, 
      'desk' => $value->{'Desk Name'}, 
      'tv' => $value->{'TV Name'}, 
      'lamp' => $value->{'Lamp Name'} 
      'carpet' => 1, 
     ]); 
    } 

    if($value->{'green'} == 1) 
    { 
     DB::table('furnitures')->insert(
     [ 
      'chair' => $value->{'Chair Name'}, 
      'desk' => $value->{'Desk Name'}, 
      'tv' => $value->{'TV Name'}, 
      'lamp' => $value->{'Lamp Name'} 
      'carpet' => 2, 
     ]); 
    } 

    if($value->{'blue'} == 1) 
    { 
     DB::table('furnitures')->insert(
     [ 
      'chair' => $value->{'Chair Name'}, 
      'desk' => $value->{'Desk Name'}, 
      'tv' => $value->{'TV Name'}, 
      'lamp' => $value->{'Lamp Name'} 
      'carpet' => 3, 
     ]); 
    } 
} 

注意 '地毯' 根據顏色（紅，綠，藍）的變化值。你必須問：「爲什麼所有的條件，如果，爲什麼不否則，如果？」它的，因爲我想所有的值存儲與althought所有其他的值不同的「地毯」值相同

Answer 1

請嘗試是這樣的：

$colors = ['red' => 1, 'green' => 2, 'blue' => 3]; 
foreach ($rows as $key => $value) { 
    foreach ($colors as $color_name => $color_value) { 
     if ($value->{$color_name} == 1) { 
      DB::table('furnitures')->insert(
       [ 
        'chair' => $value->{'Chair Name'}, 
        'desk' => $value->{'Desk Name'}, 
        'tv'  => $value->{'TV Name'}, 
        'lamp' => $value->{'Lamp Name'}, 
        'carpet' => $color_value, 
       ] 
      ); 
     } 
    } 
}