我在下面的代碼中使用PHP
來將事件輸入到MySQL
表中。當我運行它時,它不會發生錯誤,並且沒有行插入到MySQL
表中。我在哪裏錯了代碼?如何在每月的第三個星期五在php/mysql中輸入事件
而且當我改變
$date = strtotime("third friday of $month[$j] $year[$i]");
到
$date = mktime(0,0,0,$month[$j],$k,$year[$i]);
它適用於所有的日子,但我在尋找每月只有第三個星期五..
<?php
if(isset($_POST['myform'])){
$day = array('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31');
$month = array('1','2','3','4','5','6','7','8','9','10','11','12');
$year = array('2011', '2012','2013', '2014', '2015', '2016');
$startday = $_POST['day'];
$eventplace = $_POST['eventplace'];
$eventname = $_POST['eventname'];
$eventtime = $_POST['eventtime'];
for($i=0; $i<count($year); $i++){
for($j=0; $j<count($month); $j++){
for($k=$startday; $k<count($day); $k = $k + 7){
$date = strtotime("third friday of $month[$j] $year[$i]");
$week = date('W', $date) ;
$query = mysql_query(" INSERT INTO caldemo(day, month, year, eventname, eventtime, eventplace, eventweek)
VALUES ('".$k."', '".$month[$j]."', '".$year[$i]."', '".$eventname."', '".$eventtime."', '".$eventplace."', '".$week."')")or die(mysql_error()) ;
}
}
}
}
?>
<form name="theform" method="post" action="caldemo.php">
<table>
<tr>
<tr>
<td>Event Venue:</td>
<td><input type="text" name="eventplace" size="50"></td>
</tr>
<tr>
<td>Event Name:</td>
<td><input type="text" name="eventname" size="50"></td>
</tr>
<tr>
<td>Event Time:</td>
<td><input type="text" name="eventtime" size="50"></td>
</tr>
<tr>
<td></td>
<td>
<input type="submit" value="Send" name="myform">
</form>
@MC_delta_T感謝您指出'strtotime('2012年1月第一個星期日'))'會給出錯誤的結果。 – air4x