MySQL的LOAD_FILE（）

Question

的正確使用我道歉，如果這是一個密集的問題，但我有一點的，以上傳圖片BLOB與預處理語句一起使用MYSQL LOAD_FILE（）的麻煩。其結果是，我不得不求助於使用到單獨的查詢，一來準備詳細的陳述，而另一個，它不準備插入我的BLOB的聲明。下面是我試過的查詢的例子：

function add_new_video() { 
    $image = $_FILES['thumbnail_file']['tmp_name']; // pass this file name to getimagesize() to determine the mime-type 
    $size_array = getimagesize($image); 
    $thumbnail_mimetype = $size_array['mime']; 
    $thumbnail_contents = file_get_contents($image); 
    $thumbnail_filesize = $size_array[3]; 
    $thumbnail_filename = $_FILES['thumbnail_file']['name']; 

    $title = $_POST['title']; 
    $summary = $_POST['summary']; 
     // Checkbox...  
     if(!empty($_POST['demo_reel'])) { 
     $demo_reel = $_POST['demo_reel']; 
    } 
    else { 
     $demo_reel = 0; 
    } 

    $query = "INSERT INTO videos (title, summary, thumbnail_filename, thumbnail_filesize, thumbnail_mimetype, thumbnail_contents, demo_reel) VALUES(?, ?, ?, ?, ?, LOAD_FILE($image), ?)"; 
    if($stmt = $this->conn->prepare($query)) { 
     $stmt->bind_param('sssssi', $title, $summary, $thumbnail_filename, $thumbnail_filesize, $thumbnail_mimetype, $thumbnail_contents, $demo_reel); 
     $stmt->execute(); 
     if($stmt->affected_rows == 1) { 
      return true; 
     } 
     else { 
      return false; 
     } 
    } 
} 

不幸的是，這個查詢失敗，我似乎無法得到任何錯誤出來。相反，這是我當前的查詢，其工作，但不使用準備好的語句，而安全性較低：

$video_filename = $_POST['file_name']; 
    $video_number = $_POST['number']; 
    $title = $_POST['title']; 
    $summary = $_POST['summary']; 
    if(!empty($_POST['demo_reel'])) { 
    $demo_reel = $_POST['demo_reel']; 
    } 
    else { 
    $demo_reel = 0; 
    } 


    $image = $_FILES['thumbnail_file']['tmp_name']; // pass this file name to  
    getimagesize() to determine the mime-type 
    $size_array = getimagesize($image); 
    $thumbnail_mimetype = $size_array['mime']; 
    $thumbnail_filesize = $size_array[3]; 
    $thumbnail_contents = addslashes(file_get_contents($image)); 
    $thumbnail_filename = $_POST['number'] . '.jpg'; 

    $query = "INSERT INTO videos (`video_filename`, `video_number`, 
    `thumbnail_contents`, `title`, `summary`, `demo_reel`, `thumbnail_filename`,  
    `thumbnail_filesize`, `thumbnail_mimetype`) VALUES ('$video_filename', 
    '$video_number', '$thumbnail_contents', '$title', '$summary', '$demo_reel', 
    '$thumbnail_filename', '$thumbnail_filesize', '$thumbnail_mimetype')"; 

    if($result = $this->conn->query($query)) {   
    return true; 
    } 
    else { 
    return false; 
    } 

由於所有的細節目前轉義，我寧願不通過使用過程中去nl2br（），然後再返回，我想兩個查詢：一個使用準備好的發言的$ _ POST變量，然後又使用和addslashes（）和文件定期報表。我希望能夠在一個準備好的聲明中完成整個插入。任何幫助和理解，非常感謝！

Answer 1

你需要的是 MySQLi send_long_data：

$stmt = $mysqli->prepare("INSERT INTO images (image) VALUES(?)"); 
//initialize the statement 
$null = NULL; 
$stmt->bind_param("b", $null); 
//bind an empty blob dummy 
$stmt->send_long_data(0, file_get_contents("osaka.jpg")); 
//send the actual data (0 is the index of the parameter to fill with the data) 
$stmt->execute();