尋找模式並使用unix替換文件中的模式

Question

我需要你的幫助在unix.i有一個文件，我有一個值聲明，我必須在調用時替換值。例如我的價值爲& abc和& ccc。現在我必須替換輸出文件中顯示的& abc和& ccc的值。

輸入文件

go to &abc=ddd; if file found &ccc=10; no the value name is &abc; and the age is &ccc;

輸出：

go to &abc=ddd; if file found &ccc=10; now the value name is ddd; and the age is 10;

Answer 1

嘗試使用SED。

#!/bin/bash 

# The input file is a command line argument. 
input_file="${1}" 

# The map of variables to their values 
declare -A value_map=([abc]=ddd [ccc]=10) 

# Loop over the keys in our map. 
for variable in "${!value_map[@]}" ; do 
    echo "Replacing ${variable} with ${value_map[${variable}]} in ${input_file}..." 
    sed -i "s|${variable}|${value_map[${variable}]}|g" "${input_file}" 
done 

這個簡單的bash腳本將用給定文件中的ddd和ccc替換爲10的abc。下面是它的工作在一個簡單的文件的例子：

$ cat file.txt 
so boo aaa abc 
duh 

abc 
ccc 
abcccc 
hmm 
$ ./replace.sh file.txt 
Replacing abc with ddd in file.txt... 
Replacing ccc with 10 in file.txt... 
$ cat file.txt 
so boo aaa ddd 
duh 

ddd 
10 
ddd10 
hmm