使用下拉菜單來從數據庫中同時排序從數據庫中取出的列表

Question

我希望標題有意義....基本上我創建了PHP腳本從數據庫中取數據並顯示，然後我寫了一些代碼以供使用一個下拉菜單來訂購這些數據。這一切工作正常，直到我試圖利用一些分頁。我可以使分頁工作，我可以做訂購工作，但不是在同一時間！目前我擁有的代碼將允許我排列列表並對其進行幾乎分類。有40個結果，我想一次顯示10個結果。當不使用訂購代碼時，我可以完美分頁，但是當我嘗試整合代碼的兩個位時，它只會顯示前10個結果，而不會給我一個選項，可以進入下一頁查看其餘的內容！ （請記住，我纔開始學習5個DAS前，所以我仍然得到認真處理它

代碼：！

如果（isset（$ _ GET [ '開始']）） {

$ _GET [ '開始'] =​​ 0;}

$ per_page = 10; $開始= $ _GET [ '開始'];

if (!$start) 
    $start = 0; 



$sort = @$_POST['order']; 
if (!empty($sort)) { 
$get = mysql_query("SELECT bookname, bookauthor, bookpub, bookisbn 
      FROM booktable 
      ORDER BY ".mysql_real_escape_string($_POST['order'])." ASC 
      LIMIT $start, $per_page"); 
} 
else { 
$get = mysql_query("SELECT bookname, bookauthor, bookpub, bookisbn 
       FROM booktable 
       ORDER BY bookname ASC 
       LIMIT $start, $per_page"); 
} 

$record_count = mysql_num_rows($get); 


?> 
<?php 
if (isset($_GET['showerror'])) 
$errorcode = $_GET['showerror']; 
else 
$errorcode = 0; 
?> 

不會包含所有的HTML垃圾和訂購菜單！

<div id="mid"> 

<?php 
echo "<table>"; 
echo "<tr>"; 
echo "<th>"; 

echo "</th>"; 
echo "<th>"; 
echo "Book Title"; 
echo "</th>"; 
echo "<th>"; 
echo "Book Author"; 
echo "</th>"; 
echo "<th>"; 
echo "Book Publisher"; 
echo "</th>"; 
echo "<th>"; 
echo "Book ISBN"; 
echo "</th>"; 
echo "<th>"; 

echo "</th>"; 
echo "</tr>"; 
while ($row = mysql_fetch_assoc($get)) 
{ 
// get data 
$bookname = $row['bookname']; 
$bookauthor = $row['bookauthor']; 
$bookpub = $row['bookpub']; 
$bookisbn = $row['bookisbn']; 



    echo "<tr>"; 
    echo "<td>"; 
    echo "<a href='addtolist.php?bookname=".$bookname."&bookauthor=".$bookauthor."&bookpub=".$bookpub."&bookisbn=".$bookisbn."'>Add to basket</a>"; 

    echo "</td>"; 

    echo "<td>"; 
    echo $bookname; 
    echo "</td>"; 

    echo "<td>"; 
    echo $bookauthor; 
    echo "</td>"; 

    echo "<td>"; 
    echo $bookpub; 
    echo "</td>"; 

    echo "<td>"; 
    echo $bookisbn; 
    echo "</td>"; 

    echo "</tr>"; 


} 

echo "</table>"; 

$prev = $start - $per_page; 
$next = $start + $per_page; 

if (!($start<=0)) 
     echo "<a href='products.php?start=$prev'>Prev</a> "; 

     //set variable for first page number 
$i=1; 

//show page numbers 
for ($x = 0; $x < $record_count; $x = $x + $per_page) 
{ 
if ($start != $x) 
    echo "<a class='pagin' href='products.php?start=$x'> $i </a>"; 
else 
    echo "<a class='pagin' href='products.php?start=$x'><b> $i </b></a>"; 
$i++; 
} 

//show next button 
if (!($start >= $record_count - $per_page)) 
     echo "<a class='pagin' href='products.php?start=$next'> Next </a>"; 
?> 

非常感謝您的閱讀！

Answer 1

Simpliest辦法只是改變$sort = @$_POST['order'];到$sort = @$_REQUEST['order'];並添加到您的分頁鏈接&order=$order