如何在2個特定模式匹配後編輯一個Unix文件插入幾行

Question

我有一個文件，內容如下。我想編輯這個文件，以便無論何時在文件中看到LTPGY模式，然後在「set t table new $ m table」行之後，插入一個帶有「FOUND」內容的新行。

輸入文件如下： -

set ra [ 1 22 3 ] LTPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 



    set ra [ 1 22 3 ] STPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 


    set ra [ 1 22 3 ] LTPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 



    set ra [ 1 22 3 ] STPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 

我所要的輸出是這樣的： -

set ra [ 1 22 3 ] LTPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    FOUND 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 



    set ra [ 1 22 3 ] STPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 


    set ra [ 1 22 3 ] LTPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    FOUND 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 



    set ra [ 1 22 3 ] STPGY 
    set a 0 
    set a1 1 

    set t [ table new $m table] 
    set a [ $t process_axis] 
    set a [ $t voltage_axis] 

Answer 1

工程與GAWK，其他awks未經測試：

gawk ' 
    /set ra/{found = /LTPGY/} 
    1; 
    index($0, "set t [ table new $m table]") && found {print "FOUND"} 
' file 

Answer 2

這可能適用於你（GNU sed）：

sed '/LTPGY/{:a;n;/set t \[ table new $m table\]/!ba;p;s/\S.*/FOUND/}' file 

將注意力集中在LTPGY後面的行上並找到所需的字符串，然後打印它，然後用所需字符串FOUND替換除前導空格以外的所有字符。