返回前面帶ID的JSON

Question

如何從我的API中提取每個JSON返回對象前面的id？

電流：

{ 
    "1516":{ 
     "id":"1516", 
     "firstname":"Aluno", 
     "lastname":"Teste", 
     "email":"teste@gmail.com", 
     "dlastaccess":"28-10-2016", 
     "coursename":"Curso Demonstra\u00e7\u00e3o" 
    } 
} 

我如何不想離開：

[ 
    { 
     "id":"1516", 
     "firstname":"Aluno", 
     "lastname":"Teste", 
     "email":"teste@gmail.com", 
     "dlastaccess":"28-10-2016", 
     "coursename":"Curso Demonstra\u00e7\u00e3o" 
    } 
] 

我想這樣做，因爲我的清單模型不能正常工作的JSON返回來的路上，所以我無法檢查所有複選框。

API：

Answer 1

這做工作：

$json = '{"1516":{"id":"1516","firstname":"Aluno","lastname":"Teste","email":"teste@gmail.com","dlastaccess":"28-10-2016","coursename":"Curso Demonstra\u00e7\u00e3o"}}'; 

$values = json_decode($json, true); 

$values = array_values($values); 

echo json_encode($values); 

回報：

[{"id":"1516","firstname":"Aluno","lastname":"Teste","email":"teste@gmail.com","dlastaccess":"28-10-2016","coursename":"Curso Demonstra\u00e7\u00e3o"}] 

Answer 2

我猜你的$結果是一個數組（或物體）的本類型：

$ result [id] = array（sql retrieve）;

因爲sql會返回結果列表，即使結果是唯一的。想象你的查詢返回了兩個結果，你怎麼能把它們分開？

嘗試：

回波json_encode（$結果[$ cursoid]）

或

回波json_encode（$結果 - > $ cursoid）

Answer 3

$cursoid = $_GET['idcurso']; 

$sql = 'SELECT 
user2.id AS ID, 
user2.firstname AS Firstname, 
user2.lastname AS Lastname, 
user2.email AS Email, 
IF (user2.lastaccess = 0,"nunca", 
DATE_FORMAT(FROM_UNIXTIME(user2.1astaccess),"%d-96m-W")) AS dLastAccess ,c.fullname AS Coursename 
FROM mdl_user_enrolments AS ue 
JOIN mdl_enrol AS e ON e.id = ue.enrolid 
JOIN mdl_course AS c ON c.id = e.courseid 
JOIN mdl_user AS user2 ON user2 .id = ue.userid 
WHERE (SELECT timeaccess FROM mdl_user_lastaccess WHERE userid=user2.id AND courseid=c.id) IS NULL and c.id = ?'; 

$params = array($cursoid); 

$result = $DB->get_records_sql($sql, $params); 
echo json_encode(array_values($result)); // You can easily access array values without their keys by array_values(array $param) function 

Answer 4

使用array_values，默認php函數

$values = $DB->get_records_sql($sql, $params); 
$result = array_values($values); 
return json_encode($result);