如何將一個字符串拆分爲ios中的一個數組的兩部分？

Question

陣列是圖像，我需要添加聲音陣列，所以我可以在一個按鈕中顯示它，當點擊按鈕時它會顯示圖像並播放聲音。
我用componentsJoinedByString方法來格式化這個符號的數組($)。 我使用stringByAppendingSting方法將它們添加在一起，所以我想我需要格式化字符串，以便我可以再次將它們分開。

NSArray *rankNum = [PlayingCard rankNumbers]; 
[rankNum componentsJoinedByString:@"$"]; 
NSArray *rankCol = [PlayingCard rankColors]; 
NSArray *rankAni = [PlayingCard rankAnimals]; 

switch (self.chosenButton) { 
    case 0: 
     return [rankNum[self.rank] stringByAppendingString:self.sound]; 
     break; 
    case 1: 
     return rankCol[self.rank]; 
     break; 
    case 2: 
     return rankAni[self.rank]; 
     break; 
    default: 
     // It should not get here 
     return nil; 
     break; 

這是聲音的數組：

+ (NSArray *) rankNumSound 
{ 
    NSArray *getNumSound = [[[SoundModel alloc] init]getSoundNumbers]; 
    return getNumSound; 
} 

Answer 1

我認爲你正在尋找這個

NSMutableArray *arrayResult = [NSMutableArray array]; 
//you should to fill your arrays with your sounds and images 
NSMutableArray *arrayImages = [NSMutableArray array]; 
NSMutableArray *arraySound = [NSMutableArray array]; 

for (int i = 0; i < [arrayImages count]-1; i++) { 

    [arrayResult addObject:[NSString stringWithFormat:@"%@$%@", [arrayImages objectAtIndex:i], [arraySound objectAtIndex:i]]]; 

} 

NSMutableArray *newArrayimages = [NSMutableArray array]; 
NSMutableArray *newArraySound = [NSMutableArray array]; 

for (int i = 0; i < [arrayResult count]; i++) { 

    NSArray *arrayResultString = [NSMutableArray array]; 

    arrayResultString = [[arrayResult objectAtIndex:i]componentsSeparatedByString:@"$"]; 

    [newArrayimages addObject:[arrayResultString objectAtIndex:0]]; 
    [newArraySound addObject:[arrayResultString objectAtIndex:1]]; 

}