檢查，如果一個字是等值線

Question

我寫了一個程序來檢查，如果字是等值線，但經過測試案例後，它說：「您的解決方案未能通過所有測試」

下面

是測試用例：

from unittest import TestCase 

class IsogramTestCases(TestCase): 
    def test_checks_for_isograms(self): 
    word = 'abolishment' 
    self.assertEqual(
     is_isogram(word), 
     (word, True), 
     msg="Isogram word, '{}' not detected correctly".format(word) 
    ) 

    def test_returns_false_for_nonisograms(self): 
    word = 'alphabet' 
    self.assertEqual(
     is_isogram(word), 
     (word, False), 
     msg="Non isogram word, '{}' falsely detected".format(word) 
    ) 

    def test_it_only_accepts_strings(self): 
    with self.assertRaises(TypeError) as context: 
     is_isogram(2) 
     self.assertEqual(
     'Argument should be a string', 
     context.exception.message, 
     'String inputs allowed only' 
    ) 

以下也是我的測試代碼。它通過了測試，但未能一些隱藏測試：

def is_isogram(word): 
if type(word) == str or len(word) != 0: 
    if not word: 
     return (word, False) 
    word = word.lower() 
    return (word, len(set(word)) == len(word)) 
else: 
    raise TypeError('Argument should be a string') 

有誰能夠告訴我什麼，我做錯了什麼？

Answer 1

由於這個問題涉及到的東西我一直在努力，我想和大家分享我的發現，使任何人誰正在尋找這個問題的澄清溶液使用它。

def is_isogram(word): 

    word = word.lower() 

    try: 

     if len(word) > 0: 

      for letter in word: 

       if word.count(letter) > 1: 

        return (word, False) 

      return (word, True) 

     else: 
      return ('argument', False) 

    except TypeError as e: 

    return "Argument should be a string: "+ str(e) 

print is_isogram("") 

Answer 2

好吧，這個作品，也通過了所有隱藏的測試。歡迎您

def is_isogram(word): 
    '''This function tests for isogram''' 
    word_set = set(word) 

    if word.strip() == "": 
     return (word, False) 

    elif len(word) == len(word_set): 
     return (word, True) 

    elif type(word)!= str : 
     raise TypeError 

    else: 
     return (word, False) 

Answer 3

def is_isogram(word): 
    return (word,True) if word and len(set(word)) == len(word) else (word,False)