接收到大多數結果爲Define the constructor, homeboy
的此錯誤。深入瞭解我所犯的錯誤,因爲我認爲它是在我的課堂上定義的。我對Java很新,如果它很明顯,不要撕碎我。Java構造函數錯誤:已定義構造函數,未找到
Error: constructor KServer in class KServer cannot be applied to given types;
KServer server = new KServer(port);
required: no arguments
found: int
reason: actual and formal argument lists differ in length
1 error
KServer.java
public class KServer {
private int port;
//isn't this the constructor defined?
public void KServer(int PORT) {
port = PORT;
}
public void Run() {...}
}
KServ.java
public class KServ {
public static void main(String[] args) {
if (args.length != 1) {
System.err.println("Usage: java KServ <port number>");
System.exit(1);
}
int port = Integer.parseInt(args[0]);
KServer server = new KServer(port);
server.Run();
}
}
從您的「構造函數」 – Reimeus
中刪除'void'關鍵字,它必須是noob錯誤。拉屎。它在技術上不是無效的嗎? – Chemistpp
一個構造函數沒有返回類型 - 所以我想你的「構造函數」被解釋爲方法 – Rhayene