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我想知道是否可以爲Web服務請求輸入參數分配默認值。下面是在WSDL我的輸入參數:是否可以爲Web服務請求輸入參數分配默認值
<element name="pensionType" default="0" type="int">
在代碼方面我檢查pensionType像這樣的值:
if (pensionType!=0)
{ TODO code here}
else
{ return warning that no data found}
我在Mozilla測試海報此。因此,我預計如果我沒有給養老金提供任何價值,我會得到這個警告。我弄了半天錯誤:
System.Web.Services.Protocols.SoapException: Server was unable to read request. ---> System.InvalidOperationException: There is an error in XML document (13, 39). ---> System.FormatException: Input string was not in a correct format. at System.Number.StringToNumber(String str, NumberStyles options, NumberBuffer& number, NumberFormatInfo info, Boolean parseDecimal) at System.Number.ParseInt32(String s, NumberStyles style, NumberFormatInfo info) at System.Xml.XmlConvert.ToInt32(String s) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReader1.Read44_getFileTypesRequest(Boolean isNullable, Boolean checkType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReader1.Read45_getFileTypes(Boolean isNullable, Boolean checkType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReader1.Read62_getFileTypes() at Microsoft.Xml.Serialization.GeneratedAssembly.ArrayOfObjectSerializer24.Deserialize(XmlSerializationReader reader) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) --- End of inner exception stack trace --- at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle) at System.Web.Services.Protocols.SoapServerProtocol.ReadParameters() --- End of inner exception stack trace --- at System.Web.Services.Protocols.SoapServerProtocol.ReadParameters() at System.Web.Services.Protocols.WebServiceHandler.CoreProcessRequest(